• ...y that the Fourier transform is a non-zero constant multiple of a low-pass filter with gain 1 and cutoff <math>3 \pi</math> and conclude from there; you woul
    3 KB (431 words) - 10:28, 11 November 2011
  • ...'c''</sub>''t'').</span> Then feed the resulting signal through a low pass filter with a gain of 2 and a cutoff frequency of <span class="texhtml">ω<sub>''c b) Multiply by cos(w<sub>c</sub>t) then pass it through a Low Pass Filter with a gain of 2 and a cutoff f of w<sub>c</sub>
    2 KB (400 words) - 10:31, 11 November 2011
  • ...ignal can be recovered by filtering the sampled signal using the following filter: ...DT, one must first convert the samples to a pulse-train, and then low-pass filter. -pm </font>
    9 KB (1,462 words) - 07:01, 22 April 2011
  • ...</sub> = 1000π</span> and gain 2. The frequency response of this low pass filter is: Note that the cut-off frequency of the low pass filter can actually be anywhere between <span class="texhtml">ω<sub>''M''</sub></
    12 KB (2,109 words) - 05:58, 22 April 2011
  • **[[Practice_Question_5_ECE438F10|Practice Question 5 (filter design)]] ....m.zip zpgui3.m] A MATLAB GUI showing the effect of poles and zeros during filter design.
    10 KB (1,359 words) - 03:50, 31 August 2013
  • *[[ECE438_Week9_Quiz|LTI system and filter design]] <br/>
    900 B (121 words) - 10:39, 11 November 2011
  • *Week (7)-8: Filtering (Systems defined by Difference equations, Filter Design, DFT view of Filtering) ***Prof. Bouman's lecture notes on digital Filter design: [https://engineering.purdue.edu/~bouman/ece438/lecture/module_1/1.7
    9 KB (1,341 words) - 03:52, 31 August 2013
  • =Image processing on an Android phone - Lowpass filter an Image - C++ code= ...ore used to. The filtering itself is not really complicated: We just use a filter in form of a matrix and perform a convolution. As this is not really an iss
    3 KB (486 words) - 11:58, 20 April 2012
  • ...revious lecture, we observed that, under certain circumstances, a low-pass filter could be applied to this upsampling so to obtain the signal
    1 KB (213 words) - 06:24, 11 September 2013
  • ...this by computing the frequency response and the transfer function of that filter. In particular, we noted how the location of the poles and the zeros of the [[Category:Filter]]
    998 B (143 words) - 06:27, 11 September 2013
  • **[[Practice_Question_5_ECE438F10|Practice Question 5 (filter design)]]
    9 KB (1,273 words) - 20:52, 15 October 2011
  • ...n the location of the poles and the zeros of the transfer function of this filter and the amplitude of its frequency response. [[Category:Filter]]
    953 B (132 words) - 06:27, 11 September 2013
  • equation (moving average filter) :a. Find the impulse response h[n] for this filter. Is it of finite or infinite duration?
    5 KB (916 words) - 03:56, 31 August 2013
  • Today we discussed the relevance of "filter design" in today's world, including some open problems for which research i [[Category:Filter]]
    1 KB (221 words) - 06:28, 11 September 2013
  • ...e unit impulse response of an ideal filter in order to obtain a causal FIR filter. A MATLAB plot of the example presented in class can be viewed on [[ECE_438
    1 KB (164 words) - 06:30, 11 September 2013
  • ::#low pass filter the repeated part
    7 KB (1,108 words) - 06:02, 23 September 2014
  • A LPF (low-pass-filter) will usually be used before down-sampling to reduce aliasing. In this&nbsp ...f 4, 8, and 16. In this project we are using FIR (finite impulse response) filter.<br>The audio signal we use is part of Waving Flag, the theme song of 2010
    10 KB (1,707 words) - 10:44, 6 May 2012
  • *Filter design **[[Practice_Question_5_ECE438F10|Practice question on filter design]]
    6 KB (801 words) - 22:04, 19 April 2015
  • ...n]. We then proceed to demonstrate how to use the formula using an average filter and a 6x6 digital image. The issue of the boundary conditions was discussed
    2 KB (301 words) - 06:32, 11 September 2013
  • ...sample by factor of 5 then down sample by factor 3. To avoid aliasing, the filter was build by MATLAB embedded function "fir1" with order= 20, cut-of frequen
    2 KB (389 words) - 06:37, 25 September 2013
  • ...arate it. We then considered another filter (edge detector). Although that filter is not separable, we were able to write it as a sum of two separable filter
    2 KB (213 words) - 06:32, 11 September 2013
  • Consider the following FIR filter: a) Write a difference equation that can be used to implement this filter.
    2 KB (270 words) - 03:59, 31 August 2013
  • ...other type of filter introduced by Perona and Malik. We observed that this filter is not linear and that it allows one to smooth out an image without blurrin
    1 KB (157 words) - 06:33, 11 September 2013
  • Therefore the filter can be separate into two 1-D filters.
    3 KB (355 words) - 13:42, 4 December 2011
  • =Image processing on an Android phone - Lowpass filter an Image - Java code= ...roject was to lowpass filter an image on an Android phone using a Gaussian filter. Therefore it should be possible to either take a picture with the integrat
    7 KB (1,278 words) - 11:57, 20 April 2012
  • ...tion, signal mixing, encoding and decoding of audio signals, and real-time filter implementation. Additionally, I was involved with the development of a filt
    4 KB (676 words) - 12:21, 9 February 2012
  • ...ng a proof of the visit to a doctor with a date and time on it, so it will filter out such students who use this excuse frequently and know all the details h
    6 KB (1,023 words) - 09:24, 16 March 2012
  • ...cy filtering removes noise, but also blurs images as a result. The unsharp filter accentuates the edges of images, in an emboss like feature. The parts of th
    1 KB (196 words) - 17:45, 21 April 2013
  • so filter out them. /* Filter in daily returns on earning reports dates */
    11 KB (1,577 words) - 08:35, 23 April 2012
  • 3. \text{ Multiply step 2 by the filter } H(\rho) = |\rho| = f_c \left [ rect(\frac{f}{2f_c}) - \Lambda(\frac{f}{f_ 2. \text{ Filter the projections } \rho_{\theta}(r) \text{ with } h(r) \text{, where } H(\rh
    17 KB (2,783 words) - 01:51, 31 March 2015
  • ...t from probabilistic noise-reducing filters such as the Bayesian or Kalman filter.
    8 KB (1,176 words) - 15:15, 1 May 2016
  • ** Low Pass Filter: Smoothing (less sharp edges or details but reduces some static noise) ** High Pass Filter: Sharping (clear edge and enhance details but also emphasize noise)
    3 KB (555 words) - 08:09, 9 April 2013
  • b) Create Gaussian filter of size 5x5 with mean 0 and standard deviation 3. c) Plot Fourier Transform of filter’s impulse response in 3D.
    4 KB (573 words) - 10:15, 15 May 2013
  • ...l has probability of {1/10,2/10,4/10,2/10,1/10}. The signal goes through a filter, Z=2X^2+1. Z: output after the filter<br>
    2 KB (299 words) - 18:13, 27 February 2013
  • filter <math>h(m,n)</math> is a <math>(2N+1)\times(2N+1)</math> filter, and for each location we need 2 multiplies, so in total, we need <math>2(2 ...ated offline, if we consider that <math> a_j b_i </math> are merged in the filter <math> h(m,n)</math>, then will need <math> (2N+1)^2 </math> multiplies to
    4 KB (739 words) - 10:07, 13 September 2013
  • ''b) Create Gaussian filter of size 5x5 with mean 0 and standard deviation 3.'' ''c) Plot Fourier Transform of filter’s impulse response in 3D.''
    2 KB (348 words) - 10:50, 11 March 2013
  • The upper is the Gaussian filter, while bottom is the unsharp.
    1 KB (174 words) - 11:34, 11 March 2013
  • ...eed a 2D convolution function. So you can take the 2d fft multiply by your filter and invert. However this seems like allot of work, and I have never implime ...hat way. The example file gives you an idea of how to do this for a simple filter. Good luck!
    10 KB (1,756 words) - 08:05, 9 April 2013
  • ...this process. These artifacts can be reduced by filtering with a high pass filter prior to back-projection. For this reason, the process is also commonly ref # Filter the projections to obtain <math>g_{\theta}(r) = h(r)*p_{\theta}(r)</math>.
    9 KB (1,486 words) - 07:25, 26 February 2014
  • ...function is basically the frequency response of an ideal digital low pass filter. So if you were to build a low pass filter, its impulse response would be a sampled sinc in time as shown in figure 6.
    10 KB (1,726 words) - 07:26, 26 February 2014
  • ....m.zip zpgui3.m] A MATLAB GUI showing the effect of poles and zeros during filter design.
    8 KB (1,096 words) - 06:44, 14 December 2013
  • *Week (7)-8: Filtering (Systems defined by Difference equations, Filter Design, DFT view of Filtering) ***Prof. Bouman's lecture notes on digital Filter design: [https://engineering.purdue.edu/~bouman/ece438/lecture/module_1/1.7
    9 KB (1,353 words) - 09:04, 11 November 2013
  • ...nd last questions in part 2 of this lab, does anybody know they the RLC BP filter isn't used for the two-tone test, or why the '''in-band''' third-order inte ...in frequency) to the input signal. Thus, it would be difficult to design a filter to separate the input frequencies from these in-band distortion terms.
    1 KB (204 words) - 10:09, 15 January 2014
  • ...gnal in the frequency domain first. (Recall that you just need to low-pass-filter the ideal sampling.) Then invert the Fourier transform to get the reconstru
    2 KB (362 words) - 13:59, 26 September 2013
  • ...(t) was band-limited with <math>f_{max}<\pi /D</math> and apply a low-pass filter with gain D and cut-off <math>\pi/D</math> to <math>x_2[n]</math>.
    2 KB (335 words) - 05:55, 27 September 2013
  • 1. Use the signal generators and filters in the lab to generate and filter noise and various types of periodic signals. ...rfectly band-limited to 0-10MHz, is passed through a perfectly rectangular filter of bandwidth 18 kHz, gain 3 dB, and center frequency 455 kHz. If the RMS vo
    14 KB (2,228 words) - 12:03, 15 January 2014
  • ...r. Be sure to show how you calculated the cutoff frequency for the digital filter. ...is. Be sure to show how you calculated the cutoff frequency of the digital filter.
    3 KB (480 words) - 09:13, 27 September 2013
  • We need a high pass filter that filters our everything below 60 Hz. ...equency component. In order to remove the annual cycle, we need a low pass filter.
    6 KB (1,018 words) - 12:18, 30 September 2013
  • ...izing a few important facts about LTI systems, we defined a first filter, "Filter A", which we found had low-pass characteristics.
    2 KB (294 words) - 05:58, 14 October 2013
  • ...ssion on the topic of filtering, we defined another simple filter, called "filter B", and analysed its properties using the concept of frequency response and
    2 KB (300 words) - 05:47, 16 October 2013

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