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462 B (55 words) - 17:27, 23 April 2013
- ===BRITA Filter: Audio Filtration and FFT Visualizer=== ...ss, HPF, LPF, etc) with different Q and cutoff values to achieve the exact filter response desired. Very simple filters, such as the HPF and LPF discussed in6 KB (1,048 words) - 16:58, 24 April 2017
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4 KB (462 words) - 16:35, 10 December 2017
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0 B (0 words) - 23:18, 30 November 2019
Page text matches
- * Increasing filter size improves detection at the expense of localization14 KB (2,253 words) - 12:21, 9 January 2009
- ==[[ECE 301 Fall 2007 mboutin Filter Types|Types of Filters]]== {{:ECE 301 Fall 2007 mboutin Filter Types}}264 B (30 words) - 13:07, 9 December 2008
- | align="right" style="padding-right: 1em;" | Monday || 03/30/09 || Filter bank interpretation and efficient computation of STDTFT ||6 KB (689 words) - 07:59, 2 August 2010
- ...ndow shows the network that has been selected from the query field and the filter panel.4 KB (713 words) - 16:47, 30 November 2011
- *<math>\omega_c</math>: Cutoff frequency of a filter (<math>\omega_c > 0</math>). (For instance, lowpass filters are nonzero in2 KB (406 words) - 11:08, 12 November 2010
- ...mum amplitude one, minimum amplitude zero and period P. The ideal low pas filter is a band that goes from -fc to fc with constant amplitude one. Once filte ...but the digital filter is in the frequency domain. How do you apply this filter? Any ideas are helpful. Thanks!844 B (152 words) - 18:26, 11 February 2009
- ...trum of the rect (which is a sinc). This is effectively a coarse low pass filter to remove high frequency aliased replicas. <br> ...c^2</math> in frequency. This can also be thought of as a coarse low pass filter but with a sharper cutoff than zero-order hold. <br>906 B (143 words) - 12:40, 4 March 2009
- Plot of the frequency response of the average filter: Plot of the frequency response of the filter:950 B (132 words) - 11:52, 28 April 2009
- == Filter Design== ...ise.www.ecn.purdue.edu/VISE/ee438L/lab5/pdf/lab5a.pdf First lab on digital filter design]8 KB (1,226 words) - 11:40, 1 May 2009
- ...mboutin_DFT_windowedfilter|Graph of the magnitude of the DFT of a windowed filter]]7 KB (1,067 words) - 12:05, 25 June 2010
- ...e sufficiently close, then the signal can be reconstructed using a lowpass filter. ...ntinuous curve and represent an interpolation formula for an ideal lowpass filter H(jw):851 B (151 words) - 11:38, 8 November 2008
- ...)</math>, we can simply low-pass filter <math>x_p(t)</math> as long as the filter, ...ath>\omega_m < \omega_c < \omega_s - \omega_m </math>. Also, the low-pass filter must have a gain of <math>T</math>. This can be represented graphically as3 KB (582 words) - 06:11, 16 September 2013
- To recover, first we need a filter with amplited T when |W| < Wc.<br><br>500 B (101 words) - 16:21, 9 November 2008
- To recover, first we need a filter with amplited T when |W| < Wc. <math> x_{p}(t) ---->Filter, H(w) -----> x(t)</math>1 KB (238 words) - 16:44, 9 November 2008
- To recover, first we need a filter with amplited T when |W| < Wc. <math> x_{p}(t) ---->Filter, H(w) -----> x(t)</math>1 KB (238 words) - 05:31, 16 November 2008
- *<math>\omega_c</math>: Cutoff frequency of a filter (<math>\omega_c > 0</math>). (For instance, lowpass filters are nonzero in1 KB (178 words) - 19:31, 23 November 2008
- <math>\omega_c </math> Cut off frequency for a filter Pretty much apply a low pass filter to <math>x_p(t)</math>2 KB (349 words) - 12:09, 10 November 2008
- X(t) can be recovered exactly from Xp(t) by using a low pass filter with gain T and cut off frequency greater than Wm but less than Ws - Wm.1 KB (274 words) - 06:49, 16 September 2013
- ...alled the reconstructed signal <math>x_r(t)</math>, we must use a low pass filter with a gain of T, and a frequency in the range of <math>(\omega_m,\omega_s- We can use a transfer function to approximate this filter, and it is:3 KB (543 words) - 17:23, 10 November 2008
- ...can be used to recover the modulated signal being a common one the low pas filter,1 KB (207 words) - 17:11, 10 November 2008
- ...(t) can be recovered from its sampled version using an appropriate lowpass filter?2 KB (340 words) - 17:29, 10 November 2008
- ...in reality must of course be truncated usually by a low-pass or band-pass filter.548 B (84 words) - 17:56, 10 November 2008
- Where <math>H(\omega)</math> is a filter with gain equal to the period of the signal and a cutoff frequency of <math711 B (130 words) - 19:44, 10 November 2008
- To demodulate, multiply <math> cosw_{c}t </math> and use low pass filter with gain of 2.1 KB (270 words) - 12:35, 16 November 2008
- To recover x(t), use a low pass filter with gain <math> \frac {1}{a_0}=\frac {T}{\delta} </math>, and cut-off freq949 B (174 words) - 16:11, 16 November 2008
- ...m <math>x(t)cos^2(\omega_c t)</math>, we run the signal through a low pass filter with a gain of 2 and cut off frequency <math>\omega</math>. <math>\omega</m2 KB (356 words) - 08:49, 17 November 2008
- <math>\omega_c</math>: Band frequency for the lowpass filter used to recover the original signal from it's samples. Must be greater tha2 KB (279 words) - 12:53, 17 November 2008
- ...signal one of the signals so that it is centered at zero and use a lowpass filter with a gain of 2 and cutoff frequency greater than <math> \omega_m</math> b2 KB (344 words) - 15:55, 30 November 2010
- <math>x(t)\cos^2(\omega_ct)</math> --> a lowpass filter with a height of 2 and <math>\omega_m<\omega_c<2\omega_c-\omega_m</math> --2 KB (336 words) - 17:26, 17 November 2008
- ...constructed function <math>x_r(t)</math> can be recovered using a low pass filter created from the multiplication of the original step function generator <ma ...lution of <math>h_1(t)</math> and <math>h_2(t)</math> represent a low pass filter with a gain of T and a cutoff frequency <math>\omega_c</math> between <math2 KB (411 words) - 17:16, 17 November 2008
- ...by modulating y(t) with the same sinusoidal carrier and applying a lowpass filter to the result. Applying the lowpass filter to w(t) corresponds to retaining the first term, <math>\frac{1}{2}x(t)</mat837 B (153 words) - 19:06, 17 November 2008
- ...er than Wm and less than Ws - Wm. We process this signal through a lowpass filter and receive the output signal that is exactly x(t).805 B (160 words) - 20:06, 17 November 2008
- ...mple values. This impulse train is then processed through an ideal lowpass filter with gain T and cutoff frequency greater than \omega_M and les than \omega_21 KB (3,312 words) - 11:58, 5 December 2008
- ...mple values. This impulse train is then processed through an ideal lowpass filter with gain T and cutoff frequency greater than \omega_M and les than \omega_2 KB (254 words) - 07:05, 8 December 2008
- ...to the central limit theorem this smoothing can be approximated by several filter steps that can be computed much faster, like the simple moving average.10 KB (1,594 words) - 11:41, 24 March 2008
- ...eed a 2D convolution function. So you can take the 2d fft multiply by your filter and invert. However this seems like allot of work, and I have never implime ...hat way. The example file gives you an idea of how to do this for a simple filter. Good luck!10 KB (1,738 words) - 22:44, 7 April 2008
- *Week 7-8: Filtering (Systems defined by Difference equations, Filter Design, DFT view of Filtering) ***Prof. Bouman's lecture notes on digital Filter design: [https://engineering.purdue.edu/~bouman/ece438/lecture/module_1/1.79 KB (1,237 words) - 09:29, 5 October 2009
- *What did you do to apply the lowpass filter? -- [[User:weim|weim]] * firpm(500,... generates a 500 order Parks-Mc Clellen filter of cutoff. MATLAB uses 1 as pi and 1e-12 and 2e-12 are the cutoff freque4 KB (543 words) - 07:02, 25 August 2010
- See also deconv, conv2, convn, filter and, in the signal1 KB (204 words) - 22:28, 1 July 2009
- This can be accomplished either by a band-pass filter OR using the following system.538 B (101 words) - 17:58, 29 July 2009
- ...y modulating y(t) with the same sinusoidal carrier and applying a low pass filter to the629 B (112 words) - 18:18, 29 July 2009
- ...ck market! That's right. It is possible, from simple spectral analysis to "filter" out long-term and short term trends from any time varying data. This inclu * How? LOW PASS FILTER7 KB (1,251 words) - 11:54, 21 September 2012
- ...ess the answer. Am I supposed to take the inverse transform of the digital filter and relate it to time? My final answer would be composed of a lot of rects4 KB (628 words) - 15:47, 30 November 2010
- After Step 3, the signal is ready to be put through a discrete filter. ...s the maximum frequency of the signal equal to the cutoff frequency of the filter and will allow us to determine a sampling frequency that will satisfy the N8 KB (1,452 words) - 06:49, 16 September 2013
- ...y research interests include Signal Processing, (mainly Spectral Analysis, Filter Design and Image Processing), Digital Systems Design and Psychology (sounds2 KB (268 words) - 09:43, 14 May 2010
- ...t this can be applied is in signal reconstruction, where a low pass analog filter is used on the output of a digital-to-analog converter to attenuate unwante ...ained how up-sampling can be used to relax requirements on analog low pass filter design while decreasing signal distortion.5 KB (840 words) - 19:08, 22 September 2009
- ...act, the signal can be reconstructed back by passing it through a low-pass filter with a cut-off frequency of <math> \frac{1}{2T} </math> and a gain of <math3 KB (527 words) - 11:50, 22 September 2009
- To recover the signal, we will require a low pass filter with gain '''<math>T\,\!</math>''' and cutoff, '''<math>\frac{1}{2T}</math>3 KB (484 words) - 09:47, 23 September 2009
- ...ecover the signal, the sampled function is simply multiplied by a low-pass filter with height equal to the sampling period T, <math>{H_r}(f)</math>, to isola ...age:ReconstructFilter.png|500px|thumb|center|Sampled function with lowpass filter]]2 KB (436 words) - 19:51, 22 September 2009
- ...D in the circle is how many zeros we fill between samples and the Low Pass Filter removes the extraneous copies of the signal beyond W/D shown in the output *So, intuitively, we want to use an LPF (low pass filter) to "remove" these high frequency spikes.5 KB (847 words) - 11:54, 21 September 2012
- If we imagine that our slit aperture can be thought of as a spatial filter that only passes light through the slit and blocks light everywhere else, t2 KB (286 words) - 10:19, 23 September 2009
- *To filter this out, we can apply a low-pass filter with a cutoff frequency of around 2000 Hz. *So adding a high pass filter should remove the bear's voice completely.5 KB (822 words) - 11:54, 21 September 2012
- Two basic filters used are 1> '''Average Filter''' == '''Average Filter''' ==3 KB (426 words) - 06:03, 14 October 2009
- title('Image using Average Filter');782 B (107 words) - 06:01, 14 October 2009
- title('Image using Average Filter');787 B (108 words) - 06:06, 14 October 2009
- ...er:mboutin|Prof. Boutin]]: graph of the magnitude of the DFT of a windowed filter= Consider the ideal low-pass filter1 KB (212 words) - 11:50, 24 October 2011
- The end result after modeling is a transfer function that is an all-pole filter with a gain and a time delay. As noted above, the transfer function is usually an all-pole filter. We can observe what the resonances, or formants, are just by looking at t5 KB (841 words) - 15:26, 10 April 2013
- periodic filter phoneme - Generally, the vocal tract transfer function is an all-pole filter2 KB (390 words) - 07:46, 14 November 2011
- ...the series for tons of translations and dilations, uses a faster approach: filter banks. ==Multi-Resoltion Analysis using Filter Banks==10 KB (1,646 words) - 11:26, 18 March 2013
- The following pictures show the original image (Lena), the image of the filter, and the filtered image (done with conv2). Note that the FFT2 are plotted a ...e filter = 1/16*[1 2 1; 2 4 2; 1 2 1], commonly referred to as an "average filter":'''</u>8 KB (1,397 words) - 11:23, 18 March 2013
- periodic filter phoneme - Generally, the vocal tract transfer function is an all-pole filter2 KB (387 words) - 07:47, 14 November 2011
- Plot of the frequency response of the average filter: Plot of the frequency response of the filter:1 KB (163 words) - 12:50, 26 November 2014
- ...g how to handle the boundaries is as important as knowing how to apply the filter to the image (at least in the context of this course). -[[User:crtaylor|Ry945 B (155 words) - 17:55, 8 December 2009
- ...of some non-linear filters for face-enhancement, such as the Perona-Malik filter that preserve sharpness and details, whilst removing noise at the same time235 B (33 words) - 22:21, 6 December 2009
- ...though I got good grade on ECE301. And the second part is basically about filter. Before you take ECE438, I also recommend that you should figure out how to17 KB (3,004 words) - 08:11, 15 December 2011
- h(x,y) → filter FREE → filter image based only on pixels: {H, K, P}5 KB (811 words) - 16:19, 19 December 2009
- ...ion evolves into a great estimation method. The more I know about particle filter for object tracking, the more I get impressions about power of random sampl6 KB (884 words) - 16:26, 9 May 2010
- ...al ( this is of course easier said than done because we then have to use a filter of the appropriate length and so on, which means another two pages of math) ...h cut off frequencies that represented those weekly variations. A low pass filter is one that passes low frequency signals but attenuates signals that have f13 KB (2,348 words) - 13:25, 2 December 2011
- **[[Practice_Question_5_ECE438F10|Practice Question 5 (filter design)]]9 KB (1,221 words) - 11:00, 22 December 2014
- *Week 7-8: Filtering (Systems defined by Difference equations, Filter Design, DFT view of Filtering) ***Prof. Bouman's lecture notes on digital Filter design: [https://engineering.purdue.edu/~bouman/ece438/lecture/module_1/1.79 KB (1,331 words) - 07:15, 29 December 2010
- ...system is an all pole filter cascaded with a time delay. The poles of this filter determine the location of the local maxima of the voiced phonemes we pronou1 KB (151 words) - 12:53, 8 November 2010
- ...o get rid of aliases, what is the cutoff frequency of digital LPF(Low-Pass Filter)?}\,\!</math>2 KB (315 words) - 10:39, 11 November 2011
- ...ore, the cut-off frequency, <math>f_c</math> of the discrete-time low-pass filter (LPF) is <math>f_c=\frac{\pi}{L}</math>, in general.3 KB (467 words) - 19:52, 20 September 2010
- ...s relationship, we concluded that, under certain circumstances, a low-pass filter could be applied to this upsampling so to obtain the signal1 KB (220 words) - 16:07, 22 September 2010
- ...rder to get rid of aliasing, what is the cut-off frequency of the low pass filter? Explain your answer. Assume that the input signal X(f) and the continuous time filter H(f) are both band limited to 1/(2T).2 KB (373 words) - 10:41, 11 November 2011
- Thus, the cut-off frequency of the LP filter is <math>\frac{\pi}{L}</math>.666 B (121 words) - 12:21, 29 September 2010
- ...it affects the reasoning here). And finally sending it through a low pass filter, the "extra" rects get filtered out so when you end up with non-zero freque5 KB (778 words) - 09:11, 1 October 2010
- ...plies that the reconstructed signal <math>x_r(t)</math> is the output of a filter when we input the impulse train of <math>x(t)</math> with period <math>T</m ...math>\text{sinc}(t/T)</math>, whose frequency response is a ideal low-pass filter with the cut-off frequency of <math>1/(2T)</math>.4 KB (751 words) - 04:56, 2 October 2011
- Q2. Suppose that the LTI filter <math>h_1</math> satifies the following difference equation between input < Then, find the inverse LTI filter <math>h_2</math> of <math>h_1</math>, which satisfies the following relatio3 KB (462 words) - 10:42, 11 November 2011
- ...aracteristics (Filter A) and another filer with band-pass characteristics (Filter B). The behavior of these two filters will be further studied when we retur867 B (122 words) - 16:21, 8 October 2010
- ...at a specific low-pass filter (filter A) and a specific band-pass filter (filter B). We noticed the two different ways of writing the transfer function (as2 KB (393 words) - 07:25, 25 October 2010
- equation (moving average filter) :a. Find the impulse response h[n] for this filter. Is it of finite or infinite duration?4 KB (661 words) - 11:22, 30 October 2011
- Q1. Consider the following second order FIR filter with the two zeros on the unit circle as shown below. The transfer function for this filter is given by <math> H(z) = (1-e^{j\theta}z^{-1})(1-e^{-j\theta}z^{-1})=1-2\c3 KB (480 words) - 10:42, 11 November 2011
- d. If we further look at the frequency response of this filter, :therefore, when <math>\theta=\pi/2</math>, it is a bandstop filter.2 KB (437 words) - 12:00, 19 October 2010
- Today in the lecture, we continued talking about filters and filter design using the transfer function. It seems like many students find it dif1 KB (174 words) - 03:53, 21 October 2010
- ...y with period <math>2 \pi</math>. It is important to remember this for any filter in discrete-time. In the last part of the lecture, we saw how the heat equa *[[ECE_301_Fall_2007_mboutin_Filter_Types|Ideal filter types in continuous-time]]: do not forget to repeat periodically every <ma2 KB (260 words) - 12:42, 22 October 2010
- Topic: Filter Design Define a two-pole band-pass filter such that2 KB (322 words) - 13:00, 26 November 2013
- d. Determineif the filter represented by the difference equation is FIR or IIR. Give reasons for your3 KB (479 words) - 10:42, 11 November 2011
- d. Filter represented by this difference equation is IIR. Because the transfer functi2 KB (441 words) - 05:42, 28 October 2010
- Q2. Consider a causal FIR filter of length M = 2 with impulse response Q5. Define a two-zero band-stop filter such that3 KB (462 words) - 10:42, 11 November 2011
- Suppose the transfer function of the filter has the form Where <math>z_1,z_2</math> are zeros of the filter.2 KB (279 words) - 17:23, 3 November 2010
- Q1. Consider a causal FIR filter of length M = 2 with impulse response3 KB (561 words) - 10:43, 11 November 2011
- Q4. Consider a 3X3 FIR filter with coefficients h[m,n] <br/> a. Find a difference equation that can be used to implement this filter.<br/>3 KB (398 words) - 10:43, 11 November 2011
- ...that <math class="inline">h\left(t\right)</math> acts as a crude low-pass filter that attenuates high-frequency power.3 KB (498 words) - 07:16, 1 December 2010
- d. Describe how the filter behaves when <math>\lambda</math> is positive and large. <br/> e. Describe how the filter behaves when <math>\lambda</math> is negative and bigger than -1. <br/>3 KB (515 words) - 10:43, 11 November 2011
- d. For large values of <math>\lambda</math>, the filter performs sharpening.<br/> e. For -1 < <math>\lambda</math> < 0, the filter performs blurring.<br/>2 KB (275 words) - 13:34, 28 November 2010
- ...quency domain perspective. We looked an an example in detail (the low-pass filter illlustrated on top of [[ECE_438_Fall_2009_mboutin_plotCSFTofbasicfilters|t808 B (107 words) - 10:56, 29 November 2010
- ...ral input signal <math>x[m,n]</math> we get the difference equation of the filter. b. Place the center of filter (i.e. where m=0,n=0) upon the pixel of image. Multiply h[m,n] with x[m,n] o2 KB (391 words) - 07:16, 30 November 2010
- ...lting in huge disturbance to the game, I feel strong obligated to design a filter to remove the noise. Each filter is used to remove corresponding frequency component.3 KB (409 words) - 08:53, 11 November 2013
- ...ms]] from [[2011 Spring ECE 301 Boutin|ECE301]]!) are utilized to convert, filter, and combine these signals and produce the images used in diagnostics.17 KB (2,368 words) - 10:53, 6 May 2012
