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- The CT signal <math>\cos{x}</math> can be both periodic and non-periodic in DT. With a sampling rate of <math>1</math> the DT signal looks like this:371 B (61 words) - 04:13, 12 September 2008
- In HW1 I used the signal cos(t-2) so I will use that as my example signal. ...4] shift and add the signal together multiple times we can get a periodic signal with period 2.397 B (76 words) - 05:07, 12 September 2008
- Pick a CT periodic signal that was posted on Rhea as part of homework 1, and create two DT signals, o Using Xujun Huang's function <math>e^t</math> I was able to create a periodic signal.912 B (139 words) - 07:02, 12 September 2008
- The above image illustrates a periodic CT triangle signal with a frequency of one radian per second. If this was mapped to a DT signal it would be periodic and look like:539 B (82 words) - 06:21, 12 September 2008
- ...ultiply the 2 outputs by a constant, and add them together to get my final signal i should get the same if i multiply the two input signals by the constant f2 KB (285 words) - 07:21, 12 September 2008
- ...sent through the system. In the other, the time delay must come after the signal being sent through the system. If the returned output is equal in both case1 KB (222 words) - 07:00, 12 September 2008
- ==Part 1: DT Signals From one CT Signal== ...rated in homework 1.4, <math>sin(x)</math>, to create two DT signals. One signal will be periodic, and the other will not.2 KB (433 words) - 08:01, 12 September 2008
- Since z[n] = w[n] the signal is time invariant.492 B (104 words) - 07:42, 12 September 2008
- I used my CT signal <math>x(t) = 3\cos(4t + \frac{\pi}{3})</math> from homework 1. The periodic signal was created by sampling .001 from 0 to 5494 B (74 words) - 08:13, 12 September 2008
- I used the signal <math> x = sin(t)\,</math> I chose the signal <math>x(t) = t^2\,</math> to make a periodic signal.1 KB (183 words) - 07:45, 12 September 2008
- ...ere is a bug in this code. The timestep in this case makes the part of the signal that is plotted is considered to small to get a full sample.853 B (162 words) - 12:08, 12 September 2008
- A system is time invariant if an input signal x(t) corresponds to the output signal y(t) despite any scaling due to time.378 B (67 words) - 13:17, 12 September 2008
- ...input signal x(t) can be shifted by (t-to) and its output will be the same signal, yet it will be shifted the same throughout the system.751 B (146 words) - 12:22, 12 September 2008
- title('CT Signal'); % change sampleing rate to be periodic DT signal1 KB (183 words) - 09:21, 12 September 2008
- ...riant if a shift in the input signal produces the same shift in the output signal.814 B (148 words) - 08:48, 12 September 2008
- =Parte Dos - Make a Periodic Signal from Non-periodic Source=1 KB (217 words) - 08:58, 12 September 2008
- ...nitude applied to it. Also if two signals are added it would be as if each signal had went through the system and then had been added.947 B (193 words) - 14:54, 12 September 2008
- In the variant example the amplitude of the signal depends on time so it is time variant392 B (72 words) - 10:10, 12 September 2008
- Let us check if the following signal is linear. Let us check if the following signal is linear1 KB (250 words) - 10:42, 12 September 2008
- 1.This is a sine function of period 2. Function is sin(pi*t). Continuous Signal. 2. '''Periodic DT Signal'''This is the discrete signal of the same function in 1 with sampling time of 0.075. I got the diagram on642 B (86 words) - 10:23, 12 September 2008
- ...espectively, then added together and passed through a system that yields a signal '''<math>Z(t)</math>'''. ...>C_2\in \mathbb{C}</math> respectively, and then added together yielding a signal '''<math>W(t)</math>'''.2 KB (401 words) - 16:12, 12 September 2008
- ...one posted under Hw 1.4 David Hartmann. I use period of 10 to create this signal to be a periodic one. The plot is shown below:310 B (57 words) - 11:05, 12 September 2008
- Periodic signal ...of the frequency of the signal will result in a non-periodic Discrete Time signal.775 B (125 words) - 17:10, 12 September 2008
- Choose the signal <math>x(t)=cos(t)</math> which is periodic. This is <math>x(t)=e^{-t}cos(20t)</math> as the nonperiodic signal.851 B (147 words) - 15:14, 12 September 2008
- "A system is called "time invariant" if for any input signal x[n] and for any <math>t_0 \epsilon \mathbb{R}</math>, the response to the369 B (62 words) - 13:01, 12 September 2008
- Now suppose we pass the signal through the system first and then delay it842 B (149 words) - 13:12, 12 September 2008
- ...variant Systems are systems that produce the same output for a given input signal that has a time shift as it would without the time shift except for that th ...then inputing it into the system and comparing the results to imputing the signal x(t) into the system and then inputing that results into the time-delay cir821 B (152 words) - 13:44, 12 September 2008
- With the value set to T0, It is sampling the signal once every period. To solve this just make the value of T0 very small compa244 B (47 words) - 13:39, 12 September 2008
- The output of the signal x1(t)=t is y1(t)=2(t+3)=2t+6. The output of the signal x2(t)=t-1 is y2(t)=2(t+3-1)=2t+4.832 B (168 words) - 14:05, 12 September 2008
- The CT signal that I have selected is x=sin(t).219 B (34 words) - 14:07, 12 September 2008
- == Create Periodic Signal ==439 B (66 words) - 14:33, 12 September 2008
- ...e signal whether you play it at 10:01 AM or 10:06 AM. This is because the signal is the same if you listen to the song now or later. This is a 5 minute tim ...on your T.V. at 10:06 AM. This is a 5 minute time shift which affects the signal that the observer sees.549 B (107 words) - 14:25, 12 September 2008
- ...is '''not Time-invariant''' as it is determined by the dealy of the Input Signal97 B (17 words) - 14:33, 12 September 2008
- ...of <math>t_0</math> yields <math>x(t-t_0)=(t-t_0)+4</math> now this input signal through the system yields <math>y(t)=5((t-t_0)+4)=5(t-t_0)+20</math>1 KB (196 words) - 14:34, 12 September 2008
- == A CT periodic signal sampled at different frequencies == == Making periodic signal by shifting and summing aperiodic signals ==769 B (126 words) - 15:32, 12 September 2008
- by sampling every <math>2*pi</math> or changing the signal to760 B (145 words) - 15:10, 12 September 2008
- The system is defiantly not time invariant. When the signal is shifted the output is shifted also but a different magnitude is applied496 B (91 words) - 15:34, 12 September 2008
- ...ting two DT signals (one periodic and one non-periodic) from a periodic CT signal== I choose <math>x(t) = sin (2\pi t),</math> which is a periodic CT signal649 B (104 words) - 16:13, 12 September 2008
- the signal is time invariant720 B (144 words) - 16:43, 12 September 2008
- ...shift in the input signal results in an identical time shift in the output signal. ...of the system is x[n] , then y[<math>n_0</math>-n] is the output when the signal is x[<math>n_o</math>- n].403 B (84 words) - 16:25, 12 September 2008
- If for any signal '''<math>X(t)\Rightarrow Y(t)</math>''' implies that '''<math>X(t - t_o)\Ri ...up 10 minutes late to lecture, he will have missed 10 minutes of lecture (signal). Therefore, ECE 301 lectures are a "time-variant" system.1 KB (204 words) - 16:51, 12 September 2008
- == PERIODIC AND NON-PERIODIC DT SIGNALS FROM A CT SIGNAL == %periodic CT signal939 B (153 words) - 18:26, 12 September 2008
- A system is time invariant if for any time shifted input signal the system produces a shifted output such that if an input <math>x(t)</math '''Time Invariant Signal'''813 B (172 words) - 17:22, 12 September 2008
- The periodic DC signal at this frequency would be: The non-periodic DC signal with frequency @ 0.6519 B (81 words) - 18:12, 12 September 2008
- The periodic part of the CT signal With the increase in scaling we can see the non periodic part of the above signal is as belows255 B (44 words) - 17:55, 12 September 2008
- ...re separately multiplied by constants a and b and the added .The resulting signal after addition can be called z(t).1 KB (282 words) - 18:13, 12 September 2008
- ...current time. The <math>t-1\,</math> is just the value of the time when a signal is inputted into a system975 B (176 words) - 11:55, 30 January 2011
- Part B) From the data ,we deduce that the system is linear and the input signal is u [n]310 B (52 words) - 18:56, 12 September 2008
- Therefore the System modifies the signal accordingly:806 B (114 words) - 10:02, 16 September 2008
- and then there exists an <math> M\!</math> for the ouput signal y(t) such that ...signal is exp(t)*cos(t), which increases in value as t increases, and this signal is quite obviously unbounded. Mathematically, this means that there exists1 KB (251 words) - 06:44, 19 September 2008
