Ans 1) The system is not time invariant .The sytem depends on the delay of input.

Input $ {x_k[n]}=\delta[n-k] $

Output

$ {y_k[n]}={(k+1)^2\delta[n-(k+1)]} $


Part B) From the data ,we deduce that the system is linear and the input signal is u [n]

Alumni Liaison

has a message for current ECE438 students.

Sean Hu, ECE PhD 2009