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| + | There are a uniform number of points in the following triangle. Find <math>f_{X}(x)</math>.<br /> | ||
| + | =Answer= | ||
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Because if y > (1 - x), there could be a possibility a corresponding x-coordinate is NOT in the triangle, the integral becomes:<br /> | Because if y > (1 - x), there could be a possibility a corresponding x-coordinate is NOT in the triangle, the integral becomes:<br /> | ||
<math>f_{X}(x) = \int_{0}^{1 - x}2 dy = 2(1 - x)</math> | <math>f_{X}(x) = \int_{0}^{1 - x}2 dy = 2(1 - x)</math> | ||
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| + | [[Main_Page_ECE302Fall2008sanghavi|Back to ECE302 Fall 2008 Prof. Sanghavi]] | ||
Latest revision as of 13:27, 22 November 2011
Problem
There are a uniform number of points in the following triangle. Find $ f_{X}(x) $.
Answer
You can only guarantee that there is both a x and y coordinate in the range 0 to 1/2. So the PMF of fXY(x, y) is as follows:
$ f_{XY}(x, y) = \left\{\begin{array}{ll} 0,& (x, y)\ not\ in\ triangle,\\ 2,& (x, y)\ in\ triangle. \end{array}\right. $
From definition, $ f_{X}(x) = \int_{-\infty}^{\infty}f_{XY}(x, y) dy $
Because if y > (1 - x), there could be a possibility a corresponding x-coordinate is NOT in the triangle, the integral becomes:
$ f_{X}(x) = \int_{0}^{1 - x}2 dy = 2(1 - x) $
