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<math> \sum_{t=-\infty}^\infty \frac{1}{1+t^2} \ </math>&nbsp;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;and wolfram said answer is '''π * coth(π)'''. is there any easier way to do that?  Yimin. Jan 20  
 
<math> \sum_{t=-\infty}^\infty \frac{1}{1+t^2} \ </math>&nbsp;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;and wolfram said answer is '''π * coth(π)'''. is there any easier way to do that?  Yimin. Jan 20  
  
:<span style="color:red"> You do not have to evaluate the sum. In particular, you do not need the peak value of that functions.  Try to guess the period directly by looking at the sum. If you have no idea how to do this, read this [[Hw1periodicECE301f08profcomments| page]] first. -pm </span>
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:<span style="color:green"> You do not have to evaluate the sum. In particular, you do not need the peak value of that functions.  Try to guess the period directly by looking at the sum. If you have no idea how to do this, read this [[Hw1periodicECE301f08profcomments| page]] first. -pm </span>
  
Yeah I'm just trying to figure out the infinite sum just for fun. Thanks.
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Yeah I'm just trying to figure out the infinite sum just for fun. <span style="color:green">(Oh excellent! -pm)</span> Thanks.
  
And for question 4, are we still using the tempo? so my guess is use step functions to cut out the rhythm we want?
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And for question 4, are we still using the tempo? so my guess is use step functions to cut out the rhythm we want? <span style="color:green"> (Yes, that's the idea. -pm)</span>
 
Then put the whole line in one equation? that will become pretty messy I guess. Yimin
 
Then put the whole line in one equation? that will become pretty messy I guess. Yimin
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: <span style="color:green"> Not too bad, if you think about it carefully. Each note can be written in a somewhat simple form. Then you just add all the notes together. -pm </span>
 
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Revision as of 04:35, 21 January 2011


In question 2e

$ x(t)= \sum_{k=-\infty}^\infty \frac{1}{1+(x-7k)^2} \ $

should it be like this?

$ x(t)= \sum_{k=-\infty}^\infty \frac{1}{1+(t-7k)^2} \ $ 

yes, it should be. The correction has been made. -pm

and I was trying to find out what the peak value is for this question but turns out to be very hard to calculate the sum

$ \sum_{t=-\infty}^\infty \frac{1}{1+t^2} \ $            and wolfram said answer is π * coth(π). is there any easier way to do that? Yimin. Jan 20

You do not have to evaluate the sum. In particular, you do not need the peak value of that functions. Try to guess the period directly by looking at the sum. If you have no idea how to do this, read this page first. -pm

Yeah I'm just trying to figure out the infinite sum just for fun. (Oh excellent! -pm) Thanks.

And for question 4, are we still using the tempo? so my guess is use step functions to cut out the rhythm we want? (Yes, that's the idea. -pm) Then put the whole line in one equation? that will become pretty messy I guess. Yimin

Not too bad, if you think about it carefully. Each note can be written in a somewhat simple form. Then you just add all the notes together. -pm

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Recent Math PhD now doing a post-doctorate at UC Riverside.

Kuei-Nuan Lin