• To find the the overall frequency response F(w) for this system, I assumed the up/down samplers canceled each *''<span style="color:red"> It is important to realize that upsampling is not the inverse of downsampling: when you upsample after having downsamp
    2 KB (383 words) - 21:03, 10 February 2009
  • *Let's pretend we waved the math wand and got the frequency domain as below. ...ntuitively, we want to use an LPF (low pass filter) to "remove" these high frequency spikes.
    5 KB (847 words) - 11:54, 21 September 2012
  • ...helped me better understand topics from very different fields (especially frequency responses, which are used extensively in controls applications). If you are ...ion between the two. Among other things, the course shows how data rates, upsampling, and downsampling are important to consider in signal processing, and it sh
    17 KB (3,004 words) - 08:11, 15 December 2011
  • ...on, the sampling frequency must be larger than the twice of maximum signal frequency, in order to avoid the aliasing when sampling. Since the maximum frequency is 750 Hz, the sampling frequency must be greater than 1500 Hz, which is
    3 KB (467 words) - 19:52, 20 September 2010
  • After the upsampling. All of the original information of x(n) will be contained in the interval Thus, the cut-off frequency of the LP filter is <math>\frac{\pi}{L}</math>.
    666 B (121 words) - 12:21, 29 September 2010
  • ...the summation during downsampling go from 0 to D-1. This is because in the frequency domain you are trying to insert D copies of the signal every <span class="t ...n>. When you then up-sample that, you basically compress everything in the frequency domain by a factor of 6 (hence why you have 6*w/6). That means your rect wi
    5 KB (778 words) - 09:11, 1 October 2010
  • ...ath>, whose frequency response is a ideal low-pass filter with the cut-off frequency of <math>1/(2T)</math>. ...requency for the impulse train was <math>F_s=1/T</math>. Thus the sampling frequency must be larger than <math>2B</math>, in order to avoid aliasing when recons
    4 KB (751 words) - 04:56, 2 October 2011
  • ...for man" does not contain an "a", then it should be very similar (from the frequency domain point of view) to the signal between "for" and "man-" in "for mankin
    2 KB (347 words) - 13:13, 12 November 2010
  • **[[Practice_Question_4_ECE438F10|Practice Question 4 (frequency domain view of sampling)]] | [[Upsampling and downsampling lab]]
    10 KB (1,359 words) - 03:50, 31 August 2013
  • ...A octave higher means twice the frequency. So, each interval is spaced by frequency ration of <math> 2^{ \frac{1}{12}} = 1.05946309</math> ...up/down sample, it can only up/down sample by a integer factor. One can't upsampling by 1.05946309.
    5 KB (820 words) - 07:19, 21 March 2013
  • Today we talked about upsampling. More specifically, we derived the relationship between the DTFT of <math>x **Review the relationship between a sampling and a downsampling (in the frequency domain).
    2 KB (335 words) - 05:55, 27 September 2013
  • ...ponse of the digital filter. Be sure to show how you calculated the cutoff frequency for the digital filter. ...r that will accomplish this. Be sure to show how you calculated the cutoff frequency of the digital filter.
    3 KB (480 words) - 09:13, 27 September 2013
  • ...y of the signal to avoid aliasing. Let's make it just twice of the highest frequency for illustration. ...of the long term trend as low frequency component and annual cycle as high frequency component. In order to remove the annual cycle, we need a low pass filter.
    6 KB (1,018 words) - 12:18, 30 September 2013
  • **[[CT Fourier Transform (frequency in hertz)|CTFT]] ...<span class="texhtml">ω</span> versus Fourier transform as a function of frequency <span class="texhtml">''f''</span> (in hertz). (Make sure to give some exam
    13 KB (1,944 words) - 16:51, 13 March 2015
  • ...ponse of the digital filter. Be sure to show how you calculated the cutoff frequency for the digital filter. ...r that will accomplish this. Be sure to show how you calculated the cutoff frequency of the digital filter.
    3 KB (486 words) - 06:19, 22 September 2014
  • ...asing, the sampling rate should be higher or equal to twice of the highest frequency of the signal. So the sampling frequency should be greater than 5000Hz.
    3 KB (564 words) - 06:24, 10 October 2014
  • ...signal. In this slecture, I will discuss about how it works and example of upsampling.<br> '''Theory'''<br> Upsampling in the frequency domain. It can be obtain in two different ways.<br> <br>&nbsp; [[Image:Ther
    2 KB (206 words) - 10:01, 14 March 2015
  • Frequency Domain View of Upsampling ...l samples of a signal to increase the sampling rate. One way to accomplish upsampling by an integer ratio of 1:D is to interpose D-1 zero samples between each pa
    5 KB (790 words) - 10:01, 14 March 2015
  • ...nt> <font size="4">[[Upsampling Slecture Molveraz|Frequency Domain View of Upsampling]] </font> ...ng errors. At the end you listed very interesting practical application of upsampling like in audio signals and images.
    6 KB (1,072 words) - 05:42, 15 October 2014
  • Upsampling with an emphasis on the frequency domain #Graphical Example in the Frequency Domain
    3 KB (565 words) - 10:01, 14 March 2015

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Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang