Upsampling with an emphasis on the frequency domain

By: Michael Deufel

  1. Introduction
  2. Derivation
  3. Graphical Example in the Frequency Domain
  4. Conclusion
  5. Questions/ Comments

1. Introduction

The purpose of Upsampling is to manipulate a signal in order to artificially increase the sampling rate. This is done by...

  1. Discretize the signal
  2. Pad original signal with zeros
  3. Take the DTFT
  4. Send through a LPF (low pass filter)
  5. Take the inverse DTFT to return to the time domain

We will overview the whole process but focus on the effect upsampling has in the frequency domain

2. Derivation

We will start with discrete signal $ x_1[n] $

now we "pad with zeros" to define $ x_2[n] $

$ x_2[n] = \begin{cases}x_1[\frac{n}{D}], & \text{if} \frac{n}{D} \in \mathbb{Z} \\0, &\text{else} \end{cases} f $

note: $ D $ must be an integer greater then one

$ x_2[n] $ can also be defined by

$ x_2[n] = \sum_{k} x_1[k] \delta[n-kD] $

Taking the DTFT of $ x_2[n] $

$ X_2(\omega) = \sum_{n} ( \sum_{k} x_1[k] \delta[n-kD]) e^{-j\omega n}) $

switching the order of the summations you can get

$ X_2(\omega)= \sum_{k}x_1[k] ( \sum_{n}\delta[n-kD]) e^{-j\omega n}) $


$ \sum_{n}\delta[n-kD]) e^{-j\omega n} = e^{-j\omega kD} $


$ X_2(\omega) = \sum_{k} x_1[k] e^{-j\omega kD} $

This is just the DTFT of the original signal scaled by D

LPF with filter that has cutoffs at $ \frac{\pi}{D} $ and $ \frac{- \pi}{D} $ to get $ Y_2(\omega) $

Lastly to return to time domain take the Inverse DTFT of $ Y_2(\omega) $ to get your up sampled signal $ y_2[n] $

3. Graphical Example in the Frequency Domain

Note: The gain in this example is 1

Fig1 deufel.jpeg

The first graph shows the signal $ X_1(w) $ which is periodic with period $ 2\pi $

The second graph shows the signal $ X_2(W) $ which is also periodic with period $ 2\pi $ but contains unwanted repetitions of the signal

The third graph shows the Final Signal after it has been passed through the LPF to remove the unwanted repetitions

In the second graph it is obvious why the signal must pass through a LPF, because the expansion in the time domain resulted in compression in the frequency domain and that has caused the signal to repeat itself with in the range of $ [-\pi,\pi] $ and this would cause the reconstruction of the signal to be inaccurate

4. Conclusion

Upsampling is an effective way to reduce time between samples of a signal without resampling the original signal.

5. Questions/Comments

You can post questions and comments on this page, Thanks questions/comments


- ECE 438 Class notes Prof. Mireille Boutin

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