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- A periodic function is one that repeats over a certain time interval. The period of the following, <math>y=sin(x)</math>, is <math>2\pi </math>.574 B (85 words) - 07:19, 14 April 2010
- =Non-period Function=597 B (102 words) - 10:11, 5 September 2008
- [[Fundamental period/frequency -- Yicheng Guo]]47 B (6 words) - 16:55, 22 July 2009
- For example, x(t)= cosw1t + cosw2t, determine the fundamental period and frequency of the signal. period T of x(t) must be s.t. T*w1 = N*2<math>\pi</math>465 B (96 words) - 17:08, 22 July 2009
- x(t) periodic with period two. &= \text{ average of } x(t) \text{ over one period} \\2 KB (324 words) - 08:08, 15 February 2011
Page text matches
- YES: <math>X(e^{j\omega})</math> is always periodic with period <math>2\pi</math>4 KB (777 words) - 11:49, 21 November 2008
- *1(a) .... The period is not 12. Check again. *1(b) .... Even with the correct period, the answer is still wrong. Check again.4 KB (815 words) - 10:57, 21 November 2008
- ...x(t)\ </math>, for all values of t. The fundamental period is the smallest period of all periods of a signal (denoted by <math> T_0\ </math>). ...x[n]\ </math>, for all values of n. the fundamental period is the smallest period of all periods of a signal (denoted by <math> N_0\ </math>).1 KB (206 words) - 16:58, 23 April 2013
- ...k, make sure you take it over one period. Since with voice recordings each period wont be exactly the same, it's a good idea to just do it over one.5 KB (834 words) - 17:26, 23 April 2013
- ...at an aperiodic signal can be viewed as a periodic singal with an infinite period." An example of choosing the decision (this is a link)!!##!!3 KB (431 words) - 17:29, 23 April 2013
- Let <math> x[n]\ </math> be a real periodic sequence with fundamental period <math> N_0\ </math> and Fourier coefficients <math> c_k = a_k+jb_k\ </math>936 B (157 words) - 12:11, 12 December 2008
- ...er than 2*B (called the Nyquist rate), in other words, more than twice per period of the highest frequency component. : To see why, look at the figure below, which is sampled at exactly twice per period, or the Nyquist rate for the signal:3 KB (591 words) - 17:24, 23 April 2013
- ...al <math> x(t)\ </math>, the signal is sampled with shifted deltas by some period T. [<math> x(t)\ </math> multiplied by <math> \sum_{-\infty}^{\infty} \delt4 KB (689 words) - 12:48, 12 December 2008
- ...ange is in the expression for sum, the last number (in this case 6) is the period (T). Note: This is what I got for problem 3.22(e).808 B (131 words) - 13:04, 18 December 2008
- ...(t+T) = x(t),<math>\forall t</math> then we say that x(t) is periodic with period T</li></ul>3 KB (532 words) - 06:43, 16 September 2013
- *<math>T</math>: Sampling period; equal to <math>\frac{2\pi}{\omega_s}</math>2 KB (406 words) - 11:08, 12 November 2010
- ...ive with period <math>2\pi</math>. So drawing phase and magnitude for one period is sufficient.1 KB (173 words) - 17:22, 2 February 2009
- ...th constant amplitude one. Once filtered (for part a), the signal is once period of the original signal that starts at -1e-4 and goes to 1e-4. The ideal sa ...m not sure what to do. I feel as if the amplitude should be adjusted by 1/period, but I am not sure. Currently, we are in the time domain, but the digital844 B (152 words) - 18:26, 11 February 2009
- Though we already know that it's just some shift/scale version with period 2*pi, here is the math behind it.2 KB (374 words) - 12:35, 17 February 2009
- ..., personally, I usually find myself can't focus on studying within a break period. For those reasons, I suggest to put the exam as where it was. BTW, just fo12 KB (2,099 words) - 07:41, 21 March 2009
- <p>Recall DFT of x(n) periodic w\ period N<br/>2 KB (376 words) - 06:44, 16 September 2013
- ...12 straitions between them in the middle of the segment, making the pitch period <math>\frac{0.1}{12} = 8.333</math>msec. I could be way off though. --[[U746 B (132 words) - 07:54, 20 April 2009
- a.pitch period is 50/10000 = 2ms. c. using the pitch period and formant frequency, draw the graph.926 B (147 words) - 07:56, 20 April 2009
- ...over period 'p' and time 't' in years. The investment 'A' is added every period. I originally got <math> A \sum_{t=0}^{n} \frac{r^t}{p^{t}} dt </math>, bu ...ct. i equals r/p. I forgot to add the investment again and again at each period. Otherwise, I should have got a simple exponential I guess. --[[User:Gbri1 KB (270 words) - 09:43, 7 October 2008
- 2. every planet having their orbit sweep out same areas while equal period. 3. if we set P as a period of revolution and set A as a radius of orbit from a foci then,397 B (73 words) - 14:30, 31 August 2008
- * [[HW1.4 Ryan Scott - Period and Non-Periodic Functions_ECE301Fall2008mboutin]] * [[HW1.4 Hang Zhang - Periodic vs Non-period Functions_ECE301Fall2008mboutin]]24 KB (3,272 words) - 06:58, 1 September 2010
- The function <math>f(t)=sin(t-T)</math> is periodic, with a period of <math>T=2\pi</math>. This means that for <math>T=2n\pi</math>, n an int ...dic function does not remain self-similar for all integer multiples of its period. A decaying exponential is an example of a non-periodic function. The dis1 KB (206 words) - 07:09, 14 April 2010
- ...d be the Cosine function. Notice that it repeat itself time to time with a period of <math>2\pi</math>645 B (90 words) - 07:11, 14 April 2010
- The Function :<math>f(x) = sin(x)\,\!</math> is a periodic function with a Period :<math>T = 2*\pi\,\!</math>. This sine wave function repeats itself every period of :<math> 2*\pi,\!</math>1 KB (180 words) - 07:13, 14 April 2010
- ...xists an integer N such that x[n+N] = x[n]. The value of N is called the "Period."1 KB (212 words) - 07:15, 14 April 2010
- * We can see repeated x^2 that repeated itself every period of 4.519 B (70 words) - 07:18, 14 April 2010
- A periodic function is a function which repeats over a period of time. A good example of periodic functions are: As you can see, this function repeats itself with a period of <math>2\pi</math>1 KB (228 words) - 07:10, 14 April 2010
- A periodic function is one that repeats over a certain time interval. The period of the following, <math>y=sin(x)</math>, is <math>2\pi </math>.574 B (85 words) - 07:19, 14 April 2010
- ...xists an integer N such that x(n+N) = x(n). The value of N is called the "period".1 KB (265 words) - 06:12, 2 February 2011
- ...the approximation is so big that it only take approximate 1 point in each period, which is not adequate for sketching the graph.437 B (78 words) - 09:54, 6 September 2008
- ...unction is a function that repeats itself after a certain time, called the period. ...function is shown below, the tangent function. The tangent function has a period of <math>pi</math>.1,003 B (148 words) - 07:21, 14 April 2010
- Since we know that tan(t) repeats itself after every period of <math> t = \pi</math> , we know that x(t) is a periodic signal.1 KB (205 words) - 07:20, 14 April 2010
- y = sinx <-- This is very basic periodic fuction.(period time = 2<math>\pi</math>) y = cosx <-- This is also very basic periodic function.(period time = 2<math>\pi</math>)742 B (104 words) - 07:23, 14 April 2010
- ...N = [any even number] would also work. N = 2 is called the '''fundamental period''' because it is the smallest of all possible N.)2 KB (279 words) - 07:18, 14 April 2010
- A periodic function is a function that has repeating values after a certain period of time and keeps repeating as time continues.732 B (100 words) - 07:24, 14 April 2010
- ==Period Functions==20 B (2 words) - 13:51, 4 September 2008
- % Sampling period3 KB (516 words) - 16:38, 4 September 2008
- ...2\pi</math> when <math>t = \frac{\pi}{5}</math>. This is the fundamental period.879 B (140 words) - 07:25, 14 April 2010
- ...gnal. It's period is 4*k, where k is an integer. However, it's fundamental period is 4.883 B (143 words) - 07:24, 14 April 2010
- j^n has a period of 4.856 B (140 words) - 07:26, 14 April 2010
- ...mplitude of the function. When the graphs of two functions having the same period and frequency repeat at different values of the independent variable (x), t An aperiodic function (non-periodic function) is one that has no period which repeats itself (not to be confused with an antiperiodic function for2 KB (274 words) - 07:27, 14 April 2010
- ...:sinwave_ECE301Fall2008mboutin.jpg|thumb|A wavy sinusoidal wave that has a period of 2 pi]]634 B (89 words) - 07:28, 14 April 2010
- In discrete time, a function is period if there exists an integer N such that x[n+N] = x[n] ...ample of a continuous time periodic function would be x(t) = cos(t) with a period of 2*pi.796 B (137 words) - 07:18, 14 April 2010
- Periodic functions are functions that repeat over and over for a specific period. More specifically, a function is periodic if there exists some number T>0 One common example of this is the tangent function, which has a period of \pi.648 B (117 words) - 20:01, 4 September 2008
- x[n]=j^n, is periodical with fundemental period N0=4.835 B (141 words) - 07:26, 14 April 2010
- ...ere exists a number such that x(t+T) = x(t). The value of T is called the "period". ...'''''integer''''' N such that x[n+N] = x[n]. The value of N is called the "period".873 B (149 words) - 17:24, 4 September 2008
- ...has a fundamental period of two Pi. Therefore any multiple of two Pi is a period.1 KB (221 words) - 12:21, 5 September 2008
- ...strated above, the function is clearly periodic, and has 4 as the smallest period.656 B (115 words) - 06:13, 5 September 2008
- A function is period if there is a time interval <math>T > 0\!</math>, such that the value for t ...fundamental period. Every other value of <math>T\!</math> is just another period.2 KB (300 words) - 20:02, 4 September 2008
- Note: N is the period of the signal.1 KB (209 words) - 09:49, 5 September 2008
- Over an infinite period of time <br>647 B (89 words) - 21:00, 4 September 2008
- ...such that <math>\,x(t+T)=x(t)\,</math>. In this example, the fundamental period is <math>\,2\pi\,</math>, which one possible value for <math>\,T\,</math>.960 B (150 words) - 21:01, 4 September 2008
- ...> gives the original function since <math>2\pi</math> is the ''fundamental period'' of <math>x(t) = sin(t)</math> ...that <math>x[n + N] = x[n]</math> for all <math>n</math>. The fundamental period of the sine function is <math>2\pi</math>, which is not an integer. Further1 KB (189 words) - 21:21, 4 September 2008
- y = sin(3x) is a continuous function and has a period of 2pi/3, like shown on the graph below.438 B (72 words) - 21:53, 4 September 2008
- The first signal is a triangular wave which has period of 10 seconds. The second signal is a bunch of noises.656 B (87 words) - 21:36, 4 September 2008
- For all Y(t) and Y(x) Y is equal to 2. The period can be any integer greater than except 0.175 B (35 words) - 03:36, 5 September 2008
- For all Y(t) and Y(x) Y is equal to 2. The period can be any integer greater than except 0.685 B (102 words) - 07:16, 14 April 2010
- ...shift should not effect the energy or power of periodic function over one period (0 to 2<math>\pi</math> in this case).1 KB (169 words) - 18:20, 5 November 2010
- x(t) = <math>e^{n*j*w*t}</math> can be a periodic function. The period is <math>(2 * pi) / w</math>. If <math>w / (2 * pi)</math> is a rational n831 B (141 words) - 08:17, 5 September 2008
- ...r all values of t ,for some T not equal to zero,then x(t) is periodic with period T. ...(n)=x(n+N) for all values of n ,some integer N ,then x(n) is periodic with period N.960 B (171 words) - 07:13, 14 April 2010
- ...after 4 and after every 4 values. So the given function is periodic with a period of 4.566 B (79 words) - 09:16, 5 September 2008
- In CT the cosine function cos(t) is a periodic function with fundamental period T = 2π. This comes from the definition of periodic systems. A function x(563 B (104 words) - 09:23, 5 September 2008
- =Non-period Function=597 B (102 words) - 10:11, 5 September 2008
- ...ence of a single period instead of multiple periods, singly periodic) with period ...is periodic with least period <math> 2\pi </math> (often simply called the period)597 B (99 words) - 14:24, 5 September 2008
- periodic functions, all with the same period. ...eated at regular intervals. More explicitly, a function f is periodic with period P greater than zero if1 KB (253 words) - 07:04, 14 April 2010
- The power over a time period t1 to t2 is calculated by The energy of <math>y(t) = e^{t}</math> over the time period 0 to 2 seconds is found as follows:1,016 B (167 words) - 15:48, 5 September 2008
- ...odic function''' is a function that repeats its values after some definite period has been added to its independent variable. This property is called periodi ...eated at regular intervals. More explicitly, a function f is periodic with period P greater than zero if2 KB (291 words) - 07:03, 14 April 2010
- ...ence of a single period instead of multiple periods, singly periodic) with period if p is the Fundamental Period813 B (113 words) - 07:03, 14 April 2010
- ...riodic function is "a function that repeats its values after some definite period has been added to its independent variable." That is to say that x(t) = x(t688 B (113 words) - 07:12, 14 April 2010
- ...odic function''' is a function that repeats its values after some definite period has been added to its independent variable. This property is called periodi The function repeats itself in a certain period which is <math>2\pi</math> so it's a periodic function.990 B (171 words) - 18:37, 5 September 2008
- === Period Function === === Non-Period Function ===942 B (142 words) - 18:30, 5 September 2008
- ...spinding to (period + number) where "number" is less than the size of the "period" over the independent variable domain, then your function is periodic!940 B (153 words) - 18:27, 5 September 2008
- I changed the sample rate to take 25 samples per period.248 B (45 words) - 11:49, 7 September 2008
- ...3 = 0.076 and Ts = 0.07, we can see that the program only samples once per period, which is not nearly enough. The way to debug this program is to decrease T734 B (115 words) - 04:01, 9 September 2008
- ...>. Plotting this signal yields a smooth waveform that repeats itself with period <math>T=2\pi</math>. ...create a signal with an arbitrary period. Presented here is a signal with period 5.3 KB (536 words) - 11:07, 10 September 2008
- The function x(t) = cos(t) is periodic in CT, as its period is 2<math>\pi</math>. However, it is not periodic in DT. period = 5;2 KB (377 words) - 06:59, 10 September 2008
- The original signal shown in the first plot is y(t) = sin(t) with a period of <math>2\pi</math>1 KB (239 words) - 06:20, 11 September 2008
- ...Ts is too high. In the original code it only sampled enough to create two period.507 B (86 words) - 16:26, 9 September 2008
- Period is 4.<br>556 B (92 words) - 15:00, 10 September 2008
- Since the Ts value is quite large,ie .07 and the period of the sinusoidal t0 = .0769 So, we cant plot 13 ycles of 13Hz accurately a452 B (76 words) - 17:31, 9 September 2008
- ...g back my own signal, <math>y = x^2 \,</math>, i'll create a signal with a period of 5units. The graph goes back to itself with the period of 5 units1 KB (196 words) - 20:31, 10 September 2008
- ...r to fix it, we need to give points more frequently by decreasing Ts (time period).464 B (81 words) - 11:11, 10 September 2008
- What this does is repeats the function with a period of 5, and creates 4 full periods.<br>1 KB (231 words) - 06:22, 11 September 2008
- The bug in the above problem is that the step time Ts=0.07 is too big as the period for one cycle To=1/f=0.0786. Thus in one there are hardly one or two points624 B (116 words) - 14:41, 10 September 2008
- ...te, in fact it is sampling at approximately the same time intervals as the period of the signal.771 B (136 words) - 15:14, 10 September 2008
- ...'''periodic'''. For instance, let <math>k=1 (k\in\mathbb{N})</math> be the period. Then, <math>f[n+k]=f[n+1]=5 \cos(2\pi (n+1))=5 \cos(2\pi n+2\pi)=5 \cos(2 Consider the period <math>P = 2 \pi k</math>. <math>x(t+P) |_{P=2 \pi} = \sum_{k \in \mathbb{Z2 KB (312 words) - 17:53, 10 September 2008
- The bug is that the period Ts is overlarge and so it cannot display the whole wave. After trial it's ok with a period about 0.01 of it.362 B (64 words) - 16:58, 10 September 2008
- The period of the signal in the continuous time domain is <math>2\pi\!</math>. However ...d in the continuous world. In fact, any multiple or factor of the signal's period in continuous time can be used as a sampling rate that will yield a periodi1 KB (227 words) - 17:24, 10 September 2008
- T0 =1/F0; %period T0 =1/F0; %period1 KB (178 words) - 18:05, 10 September 2008
- ...he signal are at distances between the points greater than the half of the period of the waveform. As a result it does not produce the correct plot.587 B (106 words) - 12:08, 11 September 2008
- ...CT signal because it follows the rule, x(t+T)=x(t). It is periodic with a period T=<math>\barwedge</math> ...non periodic signal y=x. Now this can be made periodic by shifting it by a period of t0 and adding the sum of the shifted copies.1 KB (263 words) - 09:36, 11 September 2008
- ...the graph, the values of x[n] are periodic because they repeat after every period of <math>t = 2\pi</math>.2 KB (380 words) - 10:24, 11 September 2008
- Say I choose the sampling period <math>T_s=.1\,</math> But if I choose the sampling period to be <math>T_s=.7\,</math>1 KB (186 words) - 16:24, 11 September 2008
- ...the fact that it isn't sampling enough times to plot a decent graph. The period is is 0.7 and so is the Ts value. So therefore decrease the Ts value such461 B (80 words) - 09:55, 11 September 2008
- ...id is 1/13 = 0.077 s. With the sampling rate being roughly the same as the period it is little wonder that most of the signal was not captured.476 B (79 words) - 10:21, 11 September 2008
- ...nction was chosen at random from HW1: [[HW1.4 Hang Zhang - Periodic vs Non-period Functions_ECE301Fall2008mboutin]] If <math>x(t)</math> is sampled at <math>period=0.1</math>, the function3 KB (512 words) - 06:47, 12 September 2008
- Here I use the CT signal x=sin(2*pi*t) with a period of 1 sec:727 B (118 words) - 16:11, 12 September 2008
- However, if you sample this function with a period of anything OTHER than <math>\pi</math> then you get random dots all over t1 KB (208 words) - 14:07, 11 September 2008
- ...s that the time vector interval Ts = 0.07 sec is too small compared to the period of the signal which is 1/13 <math>\approx</math> 0.0769 sec. This bug can b573 B (96 words) - 14:13, 11 September 2008
- ...the function period, meaning that it may only mark points about once every period:526 B (91 words) - 14:20, 11 September 2008