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<font size = 3>
 
<font size = 3>
 
==Outline==
 
==Outline==
 +
#Background
 
#Introduction
 
#Introduction
 
#Derivation
 
#Derivation
 
#Example
 
#Example
 
#Conclusion
 
#Conclusion
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----
  
 
----
 
----
 +
== Background ==
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<font size = 2>
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<math>{f}_{s}</math> = sampling frequency (number of samples/second) Hz
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<br>
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<math>{T}_{s}</math> = sampling period (number of seconds/sample) seconds
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<br>
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<math> {f}_{s} =  {\frac{1}{{T}_{s}}} </math>
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<br><br>
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Sampling above Nyquist frequency guarantees a bandlimited sampled CT signal's reconstruction. **add source**
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<br>
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Define Nyquist Sampling rate as <math> {f}_{s} = 2{f}_{M} </math>
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<br>
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<math>{f}_{M} </math> is max frequency of CT signal
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<br>
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 +
----
 +
  
 
----
 
----
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== Introduction ==
 
== Introduction ==
For real world application, higher sampling rates are preferred because reconstruction doesn't require filter to be as close to the ideal (sharper cutoff). **add picture & source**
+
Sampling at frequencies much larger than Nyquist requires a filter for reconstruction with a less sharp cutoff. A digital LPF can be used to then obtain the reconstructed signal.  
 +
**add picture & source**
 
<br><br>
 
<br><br>
 
Assume <math> {x}_{c}(t) </math> is a bandlimited CT signal,
 
Assume <math> {x}_{c}(t) </math> is a bandlimited CT signal,
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----
 
----
 
----
 
----
 
 
== Derivation ==
 
== Derivation ==
  
  
 
----
 
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Revision as of 15:05, 14 October 2014

Frequency Domain View of Upsampling

Why Interpolator needs a LPF after Upsampling


A slecture by ECE student Chloe Kauffman

Partly based on the ECE438 Fall 2014 lecture material of Prof. Mireille Boutin.


Outline

  1. Background
  2. Introduction
  3. Derivation
  4. Example
  5. Conclusion


Background

$ {f}_{s} $ = sampling frequency (number of samples/second) Hz
$ {T}_{s} $ = sampling period (number of seconds/sample) seconds
$ {f}_{s} = {\frac{1}{{T}_{s}}} $

Sampling above Nyquist frequency guarantees a bandlimited sampled CT signal's reconstruction. **add source**
Define Nyquist Sampling rate as $ {f}_{s} = 2{f}_{M} $
$ {f}_{M} $ is max frequency of CT signal




Introduction

Sampling at frequencies much larger than Nyquist requires a filter for reconstruction with a less sharp cutoff. A digital LPF can be used to then obtain the reconstructed signal.

**add picture & source**



Assume $ {x}_{c}(t) $ is a bandlimited CT signal, $ {x}_{1}[n] $ is a DT sampled signal of $ {x}_{c}(t) $ with sampling period $ {T}_{1} $

This leads to the question, can you use

$ {x}_{1}[n] = x_{c}(n{T}_{1}) $

to obtain

$ {x}_{u}[n] = {x}_{c}(n{T}_{u}) $, a signal sampled at a HIGHER sampling frequency than $ {x}_{1}[n] $, without having to fully reconstruct $ {x}_{c}(t) $




Derivation


Alumni Liaison

Prof. Math. Ohio State and Associate Dean
Outstanding Alumnus Purdue Math 2008

Jeff McNeal