(add introduction)
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== Introduction ==
 
== Introduction ==
For real world application, higher sampling rates are preferred because reconstruction doesn't require filter to be as close to the ideal (sharper cutoff).  
+
For real world application, higher sampling rates are preferred because reconstruction doesn't require filter to be as close to the ideal (sharper cutoff). **add picture & source**
 +
 
 +
Assume <math> {x}_{c}(t) </math> is a bandlimited CT signal,
 +
<math> {x}_{1}[n] </math> is a DT sampled signal of <math> {x}_{c}(t) </math> with sampling period <math> {T}_{1} </math>
 +
 
 +
 
 
This leads to the question, can you use  
 
This leads to the question, can you use  
  
<math> {x}_{1}[n] = x_{c}(n{T}_{1})</math>  
+
<math> {x}_{1}[n] = x_{c}(n{T}_{1})</math>
  
 
to obtain  
 
to obtain  
  
<math>{x}_{u}[n] = {x}_{c}(n{T}_{u})</math>
+
<math>{x}_{u}[n] = {x}_{c}(n{T}_{u})</math>, a signal sampled at a HIGHER sampling frequency than <math> {x}_{1}[n]</math>,
 
without having to fully reconstruct <math> {x}_{c}(t) </math>  
 
without having to fully reconstruct <math> {x}_{c}(t) </math>  
  
assume <math> {x}_{c}(t) </math> is a bandlimited CT signal,
+
 
<math> {x}_{1}[n] </math> is a DT sampled signal of <math> {x}_{c}(t) </math> with sampling period <math> {T}_{1} </math>
+
  
 
----
 
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Revision as of 14:27, 14 October 2014

Frequency Domain View of Upsampling

Why Interpolator needs a LPF after Upsampling


A slecture by ECE student Chloe Kauffman

Partly based on the ECE438 Fall 2014 lecture material of Prof. Mireille Boutin.


Outline

  1. Introduction
  2. Derivation
  3. Example
  4. Conclusion


Introduction

For real world application, higher sampling rates are preferred because reconstruction doesn't require filter to be as close to the ideal (sharper cutoff). **add picture & source**

Assume $ {x}_{c}(t) $ is a bandlimited CT signal, $ {x}_{1}[n] $ is a DT sampled signal of $ {x}_{c}(t) $ with sampling period $ {T}_{1} $


This leads to the question, can you use

$ {x}_{1}[n] = x_{c}(n{T}_{1}) $

to obtain

$ {x}_{u}[n] = {x}_{c}(n{T}_{u}) $, a signal sampled at a HIGHER sampling frequency than $ {x}_{1}[n] $, without having to fully reconstruct $ {x}_{c}(t) $




Derivation


Alumni Liaison

has a message for current ECE438 students.

Sean Hu, ECE PhD 2009