| Line 5: | Line 5: | ||
| − | + | =Template for Text practice problem ''(erase this line)''= | |
| + | <center><font size= 4> | ||
| + | '''Practice question for [[ECE201]]: "Linear circuit analysis I" ''' | ||
| + | </font size> | ||
| + | |||
| + | By: [[ECE]] student Paul Wonnacott | ||
| + | |||
| + | Topic: Voltage Division | ||
| + | |||
| + | </center> | ||
| + | ---- | ||
| + | ==Question== | ||
| + | Determine V<sub>R</sub> in the figure below. | ||
| + | |||
| + | ===Answer === | ||
| + | For this problem use voltage division. Take the ratio of the 4 ohm resistor divided by the sum of the resistances in series, which is 9 ohms, and multiply by the source voltage of 10 volts. The answer should be about 4.44 volts. | ||
| + | |||
| + | |||
| + | ---- | ||
| + | ==Questions and comments== | ||
| + | If you have any questions, comments, etc. please post them below | ||
| + | |||
| + | ---- | ||
| + | |||
Revision as of 17:00, 14 April 2015
Contents
Paul_Wonnacott_Voltage_Division_ECE201S15
Template for Text practice problem (erase this line)
Practice question for ECE201: "Linear circuit analysis I"
By: ECE student Paul Wonnacott
Topic: Voltage Division
Question
Determine VR in the figure below.
Answer
For this problem use voltage division. Take the ratio of the 4 ohm resistor divided by the sum of the resistances in series, which is 9 ohms, and multiply by the source voltage of 10 volts. The answer should be about 4.44 volts.
Questions and comments
If you have any questions, comments, etc. please post them below
