Line 5: Line 5:
 
'''LECTURE THEME''' :
 
'''LECTURE THEME''' :
 
- ''Discriminant Functions''
 
- ''Discriminant Functions''
 +
  
 
'''Discriminant Functions''': one way of representing classifiers
 
'''Discriminant Functions''': one way of representing classifiers
Line 23: Line 24:
  
 
In other words, we can take <math>g_i(x) \rightarrow f(g_i(x))</math> for any monotonically increasing function ''f''.
 
In other words, we can take <math>g_i(x) \rightarrow f(g_i(x))</math> for any monotonically increasing function ''f''.
 +
  
 
'''Relation to Bayes Rule'''
 
'''Relation to Bayes Rule'''
Line 39: Line 41:
  
 
<math>\Longleftrightarrow g_i(\mathbf(x)) = ln(p(\mathbf(x)|\omega_i)P(\omega_i)) = ln(p(\mathbf(x)|\omega_i))+ln(P(\omega_i)</math>
 
<math>\Longleftrightarrow g_i(\mathbf(x)) = ln(p(\mathbf(x)|\omega_i)P(\omega_i)) = ln(p(\mathbf(x)|\omega_i))+ln(P(\omega_i)</math>
 +
 +
'''OR''' we can take
 +
 +
<math> g_i(\mathbf(x)) = ln(p(\mathbf(x)|\omega_i)P(\omega_i)) = ln(p(\mathbf(x)|\omega_i))+ln(P(\omega_i)</math>
 +
 +
We can take any <math>g_i</math> as long as they have the same ordering in value as specified by Bayes rule.
 +
 +
Some useful links:
 +
 +
- Bayes Rule in notes: https://engineering.purdue.edu/people/mireille.boutin.1/ECE301kiwi/Lecture4
 +
 +
- Bayesian Inference: http://en.wikipedia.org/wiki/Bayesian_inference
 +
 +
 +
'''Relational Decision Boundary'''
 +
 +
Ex :  take two classes <math>\omega_1</math> and <math>\omega_2</math>
 +
 +
<math>g(\vec x)=g_1(\vec x)-g_2(\vec x)</math>
 +
 +
decide <math>\omega_1</math> when <math>g(\vec x)>0 </math>
 +
 +
and <math>\omega_2</math> when <math>g(\vec x)<0 </math>
 +
 +
when <math>g(\vec x) = 0 </math>, you are at the decision boundary ( = hyperplane)

Revision as of 15:58, 10 March 2008

ECE662 Main Page

Class Lecture Notes

LECTURE THEME : - Discriminant Functions


Discriminant Functions: one way of representing classifiers

Given the classes $ \omega_1, \cdots, \omega_k $

The discriminant functions $ g_1(x),\ldots, g_K(x) $ such that $ g_i(x) $ n-dim S space $ \rightarrow \Re $

which are used to make decisions as follows:

decide $ \omega_i $ if $ g_i(x) \ge g_j(x), \forall j $

Note that many different choices of $ g_i(x) $ will yield the same decision rule, because we are interested in the order of values of $ g_i(x) $ for each x, and not their exact values.

For example: $ g_i(x) \rightarrow 2(g_i(x)) $ or $ g_i(x) \rightarrow ln(g_i(x)) $

In other words, we can take $ g_i(x) \rightarrow f(g_i(x)) $ for any monotonically increasing function f.


Relation to Bayes Rule

e.g. We can take $ g_i(\mathbf(x)) = P(\omega_i|\mathbf(x)) $

then $ g_i(\mathbf(x)) > g_j(\mathbf(x)), \forall j \neq i $

$ \Longleftrightarrow P(w_i|\mathbf(X)) > P(w_j|\mathbf(X)), \forall j \neq i $

OR we can take

$ g_i(\mathbf(x)) = p(\mathbf(x)|\omega_i)P(\omega_i) $

then $ g_i(\mathbf(x)) > g_j(\mathbf(x)), \forall j \neq i $

$ \Longleftrightarrow g_i(\mathbf(x)) = ln(p(\mathbf(x)|\omega_i)P(\omega_i)) = ln(p(\mathbf(x)|\omega_i))+ln(P(\omega_i) $

OR we can take

$ g_i(\mathbf(x)) = ln(p(\mathbf(x)|\omega_i)P(\omega_i)) = ln(p(\mathbf(x)|\omega_i))+ln(P(\omega_i) $

We can take any $ g_i $ as long as they have the same ordering in value as specified by Bayes rule.

Some useful links:

- Bayes Rule in notes: https://engineering.purdue.edu/people/mireille.boutin.1/ECE301kiwi/Lecture4

- Bayesian Inference: http://en.wikipedia.org/wiki/Bayesian_inference


Relational Decision Boundary

Ex : take two classes $ \omega_1 $ and $ \omega_2 $

$ g(\vec x)=g_1(\vec x)-g_2(\vec x) $

decide $ \omega_1 $ when $ g(\vec x)>0 $

and $ \omega_2 $ when $ g(\vec x)<0 $

when $ g(\vec x) = 0 $, you are at the decision boundary ( = hyperplane)

Alumni Liaison

ECE462 Survivor

Seraj Dosenbach