(New page: Infinite Geometric Series: <math>\sum_{k=0}^\infty x^k = \frac{1}{1-x} </math> provided that <math> |x|<1 </math> (else it diverges).) |
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− | + | <math>\sum_{k=0}^\infty x^k = \left\{ \begin{array}{ll} \frac{1}{1-x}&, \text{ if } |x|\leq 1\\ \text{diverges} &, \text{ else }\end{array}\right. </math> |
Latest revision as of 10:20, 4 February 2013
$ \sum_{k=0}^\infty x^k = \left\{ \begin{array}{ll} \frac{1}{1-x}&, \text{ if } |x|\leq 1\\ \text{diverges} &, \text{ else }\end{array}\right. $