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=[[Homework_1_ECE301Fall2008mboutin|HW1]], [[ECE301]], Fall 2008, [[user:mboutin|Prof. Boutin]]=
 
=[[Homework_1_ECE301Fall2008mboutin|HW1]], [[ECE301]], Fall 2008, [[user:mboutin|Prof. Boutin]]=
 
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==Question==
 
==Question==
  
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<math>x(t)=cos(t)</math>.
 
<math>x(t)=cos(t)</math>.
 
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==Energy==
 
==Energy==
 
We will find the energy in one cycle of the cosine waveform.
 
We will find the energy in one cycle of the cosine waveform.
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<math>=\frac{1}{2}</math>
 
<math>=\frac{1}{2}</math>
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[[Homework_1_ECE301Fall2008mboutin|Back to HW1, ECE301]]

Revision as of 13:40, 24 February 2015


HW1, ECE301, Fall 2008, Prof. Boutin


Question

Compute the power and energy of the signal

$ x(t)=cos(t) $.


Energy

We will find the energy in one cycle of the cosine waveform.

$ E=\int_0^{2\pi}{|cos(t)|^2dt} $


$ =\frac{1}{2}\int_0^{2\pi}(1+cos(2t))dt $


$ =\frac{1}{2}(t+\frac{1}{2}sin(2t))|_{t=0}^{t=2\pi} $


$ =\frac{1}{2}(2\pi+0-0-0) $


$ =\pi $

Energy

We will find the average power in one cycle of the cosine waveform.

$ E=\frac{1}{2\pi-0}\int_0^{2\pi}{|cos(t)|^2dt} $


$ =\frac{1}{2\pi-0}\frac{1}{2}\int_0^{2\pi}(1+cos(2t))dt $


$ =\frac{1}{4\pi}(t+\frac{1}{2}sin(2t))|_{t=0}^{t=2\pi} $


$ =\frac{1}{4\pi}(2\pi+0-0-0) $


$ =\frac{1}{2} $


Back to HW1, ECE301

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