Revision as of 05:45, 20 July 2009 by Mboutin (Talk | contribs)

$ \sum_{n = M}^N \alpha^n = \alpha^M - \alpha^{N-1} / (1 - \alpha) $

  • What if $ \alpha=1 $????
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Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood