Latest revision as of 10:28, 11 November 2011

Practice Question on Computing the Fourier Transform of a Discrete-time Signal

Compute the Fourier transform of the signal

$ x[n] = u[n+1]-u[n-2].\ $

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Answer 1

$ \mathcal X (\omega) = \sum_{n=-\infty}^\infty (u[n+1]-u[n-2])e^{-j\omega n}=\sum_{n=-1}^2 e^{-j\omega n}= $

$ \mathcal X (\omega) = e^{j\omega}+1+e^{-j\omega}+e^{-j2\omega} $

--Cmcmican 19:57, 28 February 2011 (UTC)

TA's comments: You have a small mistake in that. Note that $ u[n-2] $ starts at $ n=2 $ and not $ n=3 $.

Answer 2

So it should be like this.

$ \mathcal X (\omega) = \sum_{n=-\infty}^\infty (u[n+1]-u[n-2])e^{-j\omega n}=\sum_{n=-1}^1 e^{-j\omega n}= $

$ \mathcal X (\omega) = e^{j\omega}+1+e^{-j\omega} $

--Cmcmican 11:57, 2 March 2011 (UTC)

Answer 3

Write it here.

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