| Line 1: | Line 1: | ||
| − | + | [[Category: ECE]] | |
| + | [[Category: ECE 301]] | ||
| + | [[Category: Summer]] | ||
| + | [[Category: 2008]] | ||
| + | [[Category: asan]] | ||
| + | [[Category: Bonus]] | ||
Given: | Given: | ||
Revision as of 10:26, 21 November 2008
Given:
$ y[n]=x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k]) $
- $ x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k]) $
- $ k'=n-k $
- $ x[n]*h[n]=\sum_{k'=\infty}^{-\infty}(x[n-k']h[k']) $ from 1 and 2
- $ x[n]*h[n]=h[n]*x[n] $
