Revision as of 07:48, 22 June 2009 by Tnakachi (Talk | contribs)

$ x(t) =\sqrt x $

$ E_\infty = \int_{-\infty}^\infty x(t) dt $

$ E_\infty = \int_{-\infty}^\infty \sqrt x dt E_\infty = \int_{-\infty}^0 j \sqrt -x dt + \int_0^\infty \sqrt x dt $

Solving for the two parts of $ E_\inf $:

$ \int_{-\infty}^0 j \sqrt -x dt = \dfrac {0 + \infty}{2} $ and $ \int_0^\infty \sqrt t dt = \dfrac{\infty + 0}{2} $

Therefore: $ E_\infty = \infty $



Solving for $ P_\infty $

$ P_\infty = \lim_{t\to\infty} \int_{-t}^t x(t)d\tau $

$ P_\infty = \lim_{t\to\infty} \int_{-t}^t \sqrt t d\tau $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood