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<math> \delta (t)--->1 \!</math>
+
<math> x(t)=\delta (t)\longrightarrow {\mathcal X}(\omega)=1 \!</math>

Latest revision as of 12:15, 14 November 2008

$ x(t)=\delta (t)\longrightarrow {\mathcal X}(\omega)=1 \! $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood