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<math>x(t)=\sum^{\infty}_{n=-\infty} \delta(t-nT) \longrightarrow {\mathcal X}(\omega)= \frac{2\pi}{T}\sum^{\infty}_{k=-\infty}\delta(w-\frac{2\pi k}{T})\,</math>

Latest revision as of 12:20, 14 November 2008

$ x(t)=\sum^{\infty}_{n=-\infty} \delta(t-nT) \longrightarrow {\mathcal X}(\omega)= \frac{2\pi}{T}\sum^{\infty}_{k=-\infty}\delta(w-\frac{2\pi k}{T})\, $

Alumni Liaison

Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010