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<math>te^{-at}u(t), \text{ where }a\text{ is real,} a>0 \rightarrow (\frac{1}{a+j\omega})^2 </math>
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<math>te^{-at}u(t), \text{ where }a\text{ is real,} a>0 \longrightarrow (\frac{1}{a+j\omega})^2 </math>

Revision as of 12:05, 14 November 2008

$ te^{-at}u(t), \text{ where }a\text{ is real,} a>0 \longrightarrow (\frac{1}{a+j\omega})^2 $

Alumni Liaison

Questions/answers with a recent ECE grad

Ryne Rayburn