Revision as of 20:03, 4 November 2008 by Jhunsber (Talk)

Okay, I'm having a bit of trouble with this one. Neither the root test nor the ratio test is pretty. Should I try to use a different test? It's kind late, so my thoughts are a bit scrambled. I think I'm gonna try to rewrite the sum and see what that gets me.

$ \frac{n!}{n^n}=\frac{(n-1)!}{n^{n-1}} $

Don't know what that will do, but we'll see. His Awesomeness, Josh Hunsberger

Nevermind, I figured it out. You just have to do a second comparison between the resultant denominator in the limit with a simpler version, and show how that the limit is less than one. If you have difficulty, just give me a shout

His Awesomeness, Josh Hunsberger

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Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

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