(New page: Okay, I'm having a bit of trouble with this one. Neither the root test nor the ratio test is pretty. Should I try to use a different test? It's kind late, so my thoughts are a bit scram...)
 
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Okay, I'm having a bit of trouble with this one.  Neither the root test nor the ratio test is pretty.  Should I try to use a different test?  It's kind late, so my thoughts are a bit scrambled.  I think I'm gonna try to rewrite the sum and see what that gets me.
 
Okay, I'm having a bit of trouble with this one.  Neither the root test nor the ratio test is pretty.  Should I try to use a different test?  It's kind late, so my thoughts are a bit scrambled.  I think I'm gonna try to rewrite the sum and see what that gets me.
  
<math>\frac{n!}{n^n}=\frac{(n-1)!}{n^{n-1}}<math>
+
<math>\frac{n!}{n^n}=\frac{(n-1)!}{n^{n-1}}</math>
  
Don't know what that will do, but we'll see. ~~~
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Don't know what that will do, but we'll see. [[User:Jhunsber|His Awesomeness, Josh Hunsberger]]

Revision as of 19:50, 4 November 2008

Okay, I'm having a bit of trouble with this one. Neither the root test nor the ratio test is pretty. Should I try to use a different test? It's kind late, so my thoughts are a bit scrambled. I think I'm gonna try to rewrite the sum and see what that gets me.

$ \frac{n!}{n^n}=\frac{(n-1)!}{n^{n-1}} $

Don't know what that will do, but we'll see. His Awesomeness, Josh Hunsberger

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