Create the page "Period" on this wiki! See also the search results found.
- Over an infinite period of time <br>647 B (89 words) - 21:00, 4 September 2008
- ...such that <math>\,x(t+T)=x(t)\,</math>. In this example, the fundamental period is <math>\,2\pi\,</math>, which one possible value for <math>\,T\,</math>.960 B (150 words) - 21:01, 4 September 2008
- ...> gives the original function since <math>2\pi</math> is the ''fundamental period'' of <math>x(t) = sin(t)</math> ...that <math>x[n + N] = x[n]</math> for all <math>n</math>. The fundamental period of the sine function is <math>2\pi</math>, which is not an integer. Further1 KB (189 words) - 21:21, 4 September 2008
- y = sin(3x) is a continuous function and has a period of 2pi/3, like shown on the graph below.438 B (72 words) - 21:53, 4 September 2008
- The first signal is a triangular wave which has period of 10 seconds. The second signal is a bunch of noises.656 B (87 words) - 21:36, 4 September 2008
- For all Y(t) and Y(x) Y is equal to 2. The period can be any integer greater than except 0.175 B (35 words) - 03:36, 5 September 2008
- For all Y(t) and Y(x) Y is equal to 2. The period can be any integer greater than except 0.685 B (102 words) - 07:16, 14 April 2010
- ...shift should not effect the energy or power of periodic function over one period (0 to 2<math>\pi</math> in this case).1 KB (169 words) - 18:20, 5 November 2010
- x(t) = <math>e^{n*j*w*t}</math> can be a periodic function. The period is <math>(2 * pi) / w</math>. If <math>w / (2 * pi)</math> is a rational n831 B (141 words) - 08:17, 5 September 2008
- ...r all values of t ,for some T not equal to zero,then x(t) is periodic with period T. ...(n)=x(n+N) for all values of n ,some integer N ,then x(n) is periodic with period N.960 B (171 words) - 07:13, 14 April 2010
- ...after 4 and after every 4 values. So the given function is periodic with a period of 4.566 B (79 words) - 09:16, 5 September 2008
- In CT the cosine function cos(t) is a periodic function with fundamental period T = 2π. This comes from the definition of periodic systems. A function x(563 B (104 words) - 09:23, 5 September 2008
- =Non-period Function=597 B (102 words) - 10:11, 5 September 2008
- ...ence of a single period instead of multiple periods, singly periodic) with period ...is periodic with least period <math> 2\pi </math> (often simply called the period)597 B (99 words) - 14:24, 5 September 2008
- periodic functions, all with the same period. ...eated at regular intervals. More explicitly, a function f is periodic with period P greater than zero if1 KB (253 words) - 07:04, 14 April 2010
- The power over a time period t1 to t2 is calculated by The energy of <math>y(t) = e^{t}</math> over the time period 0 to 2 seconds is found as follows:1,016 B (167 words) - 15:48, 5 September 2008
- ...odic function''' is a function that repeats its values after some definite period has been added to its independent variable. This property is called periodi ...eated at regular intervals. More explicitly, a function f is periodic with period P greater than zero if2 KB (291 words) - 07:03, 14 April 2010
- ...ence of a single period instead of multiple periods, singly periodic) with period if p is the Fundamental Period813 B (113 words) - 07:03, 14 April 2010
- ...riodic function is "a function that repeats its values after some definite period has been added to its independent variable." That is to say that x(t) = x(t688 B (113 words) - 07:12, 14 April 2010
- ...odic function''' is a function that repeats its values after some definite period has been added to its independent variable. This property is called periodi The function repeats itself in a certain period which is <math>2\pi</math> so it's a periodic function.990 B (171 words) - 18:37, 5 September 2008
- === Period Function === === Non-Period Function ===942 B (142 words) - 18:30, 5 September 2008
- ...spinding to (period + number) where "number" is less than the size of the "period" over the independent variable domain, then your function is periodic!940 B (153 words) - 18:27, 5 September 2008
- I changed the sample rate to take 25 samples per period.248 B (45 words) - 11:49, 7 September 2008
- ...3 = 0.076 and Ts = 0.07, we can see that the program only samples once per period, which is not nearly enough. The way to debug this program is to decrease T734 B (115 words) - 04:01, 9 September 2008
- ...>. Plotting this signal yields a smooth waveform that repeats itself with period <math>T=2\pi</math>. ...create a signal with an arbitrary period. Presented here is a signal with period 5.3 KB (536 words) - 11:07, 10 September 2008
- The function x(t) = cos(t) is periodic in CT, as its period is 2<math>\pi</math>. However, it is not periodic in DT. period = 5;2 KB (377 words) - 06:59, 10 September 2008
- The original signal shown in the first plot is y(t) = sin(t) with a period of <math>2\pi</math>1 KB (239 words) - 06:20, 11 September 2008
- ...Ts is too high. In the original code it only sampled enough to create two period.507 B (86 words) - 16:26, 9 September 2008
- Period is 4.<br>556 B (92 words) - 15:00, 10 September 2008
- Since the Ts value is quite large,ie .07 and the period of the sinusoidal t0 = .0769 So, we cant plot 13 ycles of 13Hz accurately a452 B (76 words) - 17:31, 9 September 2008
- ...g back my own signal, <math>y = x^2 \,</math>, i'll create a signal with a period of 5units. The graph goes back to itself with the period of 5 units1 KB (196 words) - 20:31, 10 September 2008
- ...r to fix it, we need to give points more frequently by decreasing Ts (time period).464 B (81 words) - 11:11, 10 September 2008
- What this does is repeats the function with a period of 5, and creates 4 full periods.<br>1 KB (231 words) - 06:22, 11 September 2008
- The bug in the above problem is that the step time Ts=0.07 is too big as the period for one cycle To=1/f=0.0786. Thus in one there are hardly one or two points624 B (116 words) - 14:41, 10 September 2008
- ...te, in fact it is sampling at approximately the same time intervals as the period of the signal.771 B (136 words) - 15:14, 10 September 2008
- ...'''periodic'''. For instance, let <math>k=1 (k\in\mathbb{N})</math> be the period. Then, <math>f[n+k]=f[n+1]=5 \cos(2\pi (n+1))=5 \cos(2\pi n+2\pi)=5 \cos(2 Consider the period <math>P = 2 \pi k</math>. <math>x(t+P) |_{P=2 \pi} = \sum_{k \in \mathbb{Z2 KB (312 words) - 17:53, 10 September 2008
- The bug is that the period Ts is overlarge and so it cannot display the whole wave. After trial it's ok with a period about 0.01 of it.362 B (64 words) - 16:58, 10 September 2008
- The period of the signal in the continuous time domain is <math>2\pi\!</math>. However ...d in the continuous world. In fact, any multiple or factor of the signal's period in continuous time can be used as a sampling rate that will yield a periodi1 KB (227 words) - 17:24, 10 September 2008
- T0 =1/F0; %period T0 =1/F0; %period1 KB (178 words) - 18:05, 10 September 2008
- ...he signal are at distances between the points greater than the half of the period of the waveform. As a result it does not produce the correct plot.587 B (106 words) - 12:08, 11 September 2008
- ...CT signal because it follows the rule, x(t+T)=x(t). It is periodic with a period T=<math>\barwedge</math> ...non periodic signal y=x. Now this can be made periodic by shifting it by a period of t0 and adding the sum of the shifted copies.1 KB (263 words) - 09:36, 11 September 2008
- ...the graph, the values of x[n] are periodic because they repeat after every period of <math>t = 2\pi</math>.2 KB (380 words) - 10:24, 11 September 2008
- Say I choose the sampling period <math>T_s=.1\,</math> But if I choose the sampling period to be <math>T_s=.7\,</math>1 KB (186 words) - 16:24, 11 September 2008
- ...the fact that it isn't sampling enough times to plot a decent graph. The period is is 0.7 and so is the Ts value. So therefore decrease the Ts value such461 B (80 words) - 09:55, 11 September 2008
- ...id is 1/13 = 0.077 s. With the sampling rate being roughly the same as the period it is little wonder that most of the signal was not captured.476 B (79 words) - 10:21, 11 September 2008
- ...nction was chosen at random from HW1: [[HW1.4 Hang Zhang - Periodic vs Non-period Functions_ECE301Fall2008mboutin]] If <math>x(t)</math> is sampled at <math>period=0.1</math>, the function3 KB (512 words) - 06:47, 12 September 2008
- Here I use the CT signal x=sin(2*pi*t) with a period of 1 sec:727 B (118 words) - 16:11, 12 September 2008
- However, if you sample this function with a period of anything OTHER than <math>\pi</math> then you get random dots all over t1 KB (208 words) - 14:07, 11 September 2008
- ...s that the time vector interval Ts = 0.07 sec is too small compared to the period of the signal which is 1/13 <math>\approx</math> 0.0769 sec. This bug can b573 B (96 words) - 14:13, 11 September 2008
- ...the function period, meaning that it may only mark points about once every period:526 B (91 words) - 14:20, 11 September 2008