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- The following MATLAB program attempts to plot 13 cycles of a 13 Hz sinusoid, but it has a bug. E771 B (136 words) - 15:14, 10 September 2008
- == MATLAB code == This is the faulty MATLAB code that was given to us to correct:509 B (90 words) - 17:33, 10 September 2008
- The following MATLAB code doesn't work properly since the step value, Ts, is too big. However, by reducing the step size, the MATLAB routine will print all 13 cycles of the 13Hz sinusoid.611 B (104 words) - 17:43, 10 September 2008
- == MATLAB CODE == == MATLAB CODE ==891 B (157 words) - 18:13, 10 September 2008
- ...rge and should be less than 1/26 instead. The current sampling rate causes matlab to take points the signal are at distances between the points greater than587 B (106 words) - 12:08, 11 September 2008
- Given MATLAB code The Graph of the above MATLAB code574 B (100 words) - 18:24, 10 September 2008
- Now the matlab code to achieve this would be, Note: I have referred to Wei Jian Chan's matlab program to help me get started. I hope you do not mind.1 KB (263 words) - 09:36, 11 September 2008
- MATLAB CODING2 KB (380 words) - 10:24, 11 September 2008
- == Fixing Matlab Code ==473 B (82 words) - 09:42, 11 September 2008
- == Given MATLAB Code == This MATLAB program attempts to plot 13 cycles of a 13 Hz sinusoid.449 B (75 words) - 12:24, 11 September 2008
- === Matlab Code ===2 KB (239 words) - 14:00, 11 September 2008
- ==Problem with MATLAB Code== The problem with the above MATLAB code is that the time vector interval Ts = 0.07 sec is too small compared t573 B (96 words) - 14:13, 11 September 2008
- Here is the debugged MATLAB code552 B (87 words) - 14:59, 11 September 2008
- 1. From sampling the values of a cosine function as described in the matlab code attached, the following periodic function, a simple line y = 1, was pr2 KB (242 words) - 16:14, 12 September 2008
- Matlab Code: Matlab Code:774 B (126 words) - 13:28, 12 September 2008
- ...jsin(t))</math> can be made periodic by literally repeating the signal in MATLAB. The result of this would look like the following signal:1 KB (186 words) - 16:07, 11 September 2008
- The following MATLAB code has a bug in it:530 B (95 words) - 16:13, 11 September 2008
- After running the given MATLAB code, the following plot was produced:1 KB (190 words) - 17:53, 11 September 2008
- the matlab code is as follows the matlab code is as follows1 KB (207 words) - 21:44, 11 September 2008
- The following MATLAB code cannot plot 13 cycles of a 13Hz sinusoid because this code has too lar344 B (58 words) - 04:10, 12 September 2008
- ==Matlab Code== This matlab code will achieve the desired results. All I did was make the Ts value 1/1415 B (72 words) - 04:36, 12 September 2008
- The matlab code is as follows:912 B (139 words) - 07:02, 12 September 2008
- == MATLAB CODE ==1 KB (183 words) - 09:21, 12 September 2008
- ...peat it every 2 seconds and plot it over three periods using the following MATLAB code:1 KB (217 words) - 08:58, 12 September 2008
- ...the same function in 1 with sampling time of 2. Diagram was obtained using Matlab.642 B (86 words) - 10:23, 12 September 2008
- == MATLAB CODE ==718 B (119 words) - 10:41, 12 September 2008
- The above MATLAB code is supposed to output 13 cycles of a 13 Hz sine wave. However, it ins1,020 B (176 words) - 11:10, 12 September 2008
- I haven't played around with matlab enough to know how to create the signal needed with my own code, so I used851 B (147 words) - 15:14, 12 September 2008
- The bug in the matlab code was the value of Ts set equal to 0.07. By dividing the value by 10000,411 B (70 words) - 12:57, 12 September 2008
- ...there is no N such that <math>x[n+N] = x[n]</math> for all n. (Working on matlab remotely so I couldn't post the graph)353 B (64 words) - 12:59, 12 September 2008
- * [[Matlab Code _ECE301Fall2008mboutin]] * [[Matlab Code _ECE301Fall2008mboutin]]1 KB (215 words) - 15:10, 12 September 2008
- The bug in the MATLAB program is that the sampling frequency here is uite large, as a result it i398 B (72 words) - 14:44, 12 September 2008
- %MatLab code649 B (104 words) - 16:13, 12 September 2008
- ...enough. It sampled at few points and generated different looking graph in MATLAB431 B (76 words) - 15:55, 12 September 2008
- Bugged matlab code: Correct matlab code :594 B (85 words) - 17:38, 12 September 2008
- After running the code in the Matlab, realizing that the Ts = 0.07 value is almost as big as T0=1/13=0.76. There445 B (77 words) - 18:20, 12 September 2008
- ...er, then she can easily determine the Secret Matrix (especially if she has Matlab).1 KB (212 words) - 09:45, 16 September 2008
- ...matrix and applying it to the encrypted vector to find the message. Using MATLAB (and with coding help from Ronny Wijaya), the secret matrix is, ...,23,3) and the inverse of the secret matrix, we can plug these values into MATLAB to find that the decrypted vector is (2,23,5).2 KB (360 words) - 13:19, 16 September 2008
- Matlab will tell us that the resultant matrix, the "secret" matrix, is:<br>2 KB (328 words) - 13:58, 17 September 2008
- Using MATLAB, I found the secret matrix to be:1 KB (201 words) - 06:41, 17 September 2008
- Using matlab, the secret matrix can be found in the following way:2 KB (285 words) - 11:08, 19 September 2008
- Matlab will tell us that the encryption matrix, is:<br>1 KB (189 words) - 08:46, 18 September 2008
- Using matlab, I used MATLAB. Not sure where it went wrong and why my answer is different from others. A2 KB (236 words) - 10:14, 18 September 2008
- Using MATLAB to do some matrix math, I found the secret matrix to be:1 KB (200 words) - 14:35, 18 September 2008
- ...rminants, some Gaussian methods, but we will assume he has a calculator or matlab to do it for him.3 KB (387 words) - 16:01, 18 September 2008
- We go to an enineer-in-training's favorite program Matlab and so that (sm)(es) = ds which in matlab means sm = ds*inv(es)690 B (100 words) - 19:45, 18 September 2008
- ...matrix, one for (1,0,4,0,1,0,1,0,1) and one for (2,0,0,0,1,0,0,0,3). Using matlab with the following code, we multiply the second matrix with the inverse of1 KB (195 words) - 21:24, 18 September 2008
- which can be used as matrix [A] in matlab to find the inverse matrix [B] which, when multiplied with the encrypted ve1 KB (170 words) - 15:25, 19 September 2008
- 3. Using Matlab and my extensive knowledge of the English alphabet, the decrypted message w541 B (87 words) - 12:58, 19 September 2008
- Using Matlab the "secret matrix" is found to be <math> \left[ \begin{array}{ccc}957 B (150 words) - 13:03, 19 September 2008