(New page: Category:ECE301Spring2011Boutin Category:Problem_solving ---- = Practice Question on Computing the Fourier Transform of a Continuous-time Signal = Compute the Fourier transform o...) |
|||
| Line 15: | Line 15: | ||
---- | ---- | ||
=== Answer 1 === | === Answer 1 === | ||
| − | + | ||
| + | Use answer to previous practice problem and the time shifting property. | ||
| + | |||
| + | <math>\mathfrak{F}\Bigg(s(t-t_0)\Bigg)=e^{j\omega t_0}\mathfrak{F}\Bigg(x(t)\Bigg)</math> | ||
| + | |||
| + | Therefore, | ||
| + | |||
| + | <math>\chi(\omega)=e^{j\omega \frac{\pi}{12}}2\pi \delta(\omega-2\pi k)</math> | ||
| + | |||
| + | --[[User:Cmcmican|Cmcmican]] 20:52, 21 February 2011 (UTC) | ||
| + | |||
=== Answer 2 === | === Answer 2 === | ||
Write it here. | Write it here. | ||
Revision as of 16:52, 21 February 2011
Contents
Practice Question on Computing the Fourier Transform of a Continuous-time Signal
Compute the Fourier transform of the signal
$ x(t) = \cos (2 \pi t+\frac{\pi}{12} )\ $
You will receive feedback from your instructor and TA directly on this page. Other students are welcome to comment/discuss/point out mistakes/ask questions too!
Answer 1
Use answer to previous practice problem and the time shifting property.
$ \mathfrak{F}\Bigg(s(t-t_0)\Bigg)=e^{j\omega t_0}\mathfrak{F}\Bigg(x(t)\Bigg) $
Therefore,
$ \chi(\omega)=e^{j\omega \frac{\pi}{12}}2\pi \delta(\omega-2\pi k) $
--Cmcmican 20:52, 21 February 2011 (UTC)
Answer 2
Write it here.
Answer 3
Write it here.
