(New page: Category:ECE301Spring2011Boutin Category:problem solving =Practice problem on time-invariance of a CT system= == Question == <math>Y(t) = x(t - 1) - x(1 - t)</math> It is Time...) |
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<math>Y(t) = x(t - 1) - x(1 - t)</math> | <math>Y(t) = x(t - 1) - x(1 - t)</math> | ||
It is Time Invariant? Justify. | It is Time Invariant? Justify. | ||
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== Answer == | == Answer == | ||
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<math> x(t - t_o - 1) - x(1 - t + t_o) =/= x(t - t_o - 1) - x(1 - t - t_o)</math> | <math> x(t - t_o - 1) - x(1 - t + t_o) =/= x(t - t_o - 1) - x(1 - t - t_o)</math> | ||
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== Comments== | == Comments== | ||
Please comment on this answer. Are there any mistakes? Is it clear? Could it be improved? | Please comment on this answer. Are there any mistakes? Is it clear? Could it be improved? | ||
Revision as of 06:40, 2 February 2011
Contents
Practice problem on time-invariance of a CT system
Question
$ Y(t) = x(t - 1) - x(1 - t) $
It is Time Invariant? Justify.
Answer
No.
$ S_1 = Y(t) = x(t - 1) - x(1 - t) $
$ S_2 = Y(t) = x(t - t_o) $
$ x(t) -> S1 -> S2 -> x(t - t_o - 1) - x(1 - t + t_o) $
$ x(t) -> S2 -> S1 -> x(t - t_o - 1) - x(1 - t - t_o) $
$ x(t - t_o - 1) - x(1 - t + t_o) =/= x(t - t_o - 1) - x(1 - t - t_o) $
Comments
Please comment on this answer. Are there any mistakes? Is it clear? Could it be improved?
Comment 1
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Comment 2
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