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===Answer 1===
 
===Answer 1===
Write it here.
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Yes, this system is invertible. The inverse is <math>y(t)=x(t-2)</math>
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Proof:
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<math>x(t) \to \Bigg[ system 1 \Bigg] \to y(t) = x(t+2) \to \Bigg[ inverse \Bigg] \to z(t) = y(t-2) = x((t-2)+2) = x(t)</math>
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--[[User:Cmcmican|Cmcmican]] 17:08, 24 January 2011 (UTC)
 
===Answer 2===
 
===Answer 2===
 
Write it here.
 
Write it here.

Revision as of 13:08, 24 January 2011

Practice Question on System Invertibility

The input x(t) and the output y(t) of a system are related by the equation

$ y(t)=x(t+2) $

Is the system invertible (yes/no)? If you answered "yes", find the inverse of this system. If you answered "no", give a mathematical proof that the system is not invertible.


Share your answers below

You will receive feedback from your instructor and TA directly on this page. Other students are welcome to comment/discuss/point out mistakes/ask questions too!


Answer 1

Yes, this system is invertible. The inverse is $ y(t)=x(t-2) $

Proof:

$ x(t) \to \Bigg[ system 1 \Bigg] \to y(t) = x(t+2) \to \Bigg[ inverse \Bigg] \to z(t) = y(t-2) = x((t-2)+2) = x(t) $

--Cmcmican 17:08, 24 January 2011 (UTC)

Answer 2

Write it here.

Answer 3

Write it here.


Back to ECE301 Spring 2011 Prof. Boutin

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva