(New page: <math>\sum_{k=0}^n x^k = \frac{1-x^{n+1}}{1-x} </math>) |
(No difference)
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Revision as of 08:41, 1 October 2008
$ \sum_{k=0}^n x^k = \frac{1-x^{n+1}}{1-x} $
(New page: <math>\sum_{k=0}^n x^k = \frac{1-x^{n+1}}{1-x} </math>) |
(No difference)
|
$ \sum_{k=0}^n x^k = \frac{1-x^{n+1}}{1-x} $