If n = 10,000 what interval gives you 99% confindence?

We are solving for e (epsilon)...

1 - [1/(4*n*e^2)] = .99

.01 = 1/(40000*e^2)

e = (1/20) = .05

We are 99% sure that we are within .05 of the actual p.


Back to ECE302 Fall 2008 Prof. Sanghavi

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Ruth Enoch, PhD Mathematics