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Rs only has two elements, a and c, which are elements of R. Therefore, this s is a right ideal for all 2x2 matrices.
 
Rs only has two elements, a and c, which are elements of R. Therefore, this s is a right ideal for all 2x2 matrices.
 +
 +
A field is algebraically closed if every polynomial ring’s coefficient f∈A has a root that is also in A. More simply, this means that there exists some x∈A where f(x) = 0. It is important to note that no finite field can be algebraically closed, because if the points are f<sub>1</sub> , f<sub>2</sub>, .. f<sub>n</sub>, then the polynomial (x-f<sub>1</sub>)(x-f<sub>2</sub>)…(x-f<sub>n</sub>)+1 has no zeros that are a part of F.
 +
 +
Examples: x<sup>2</sup>+1 =0. A field comprised of only real numbers is not algebraically closed because there are no real numbers that can solve this polynomial despite the fact that the polynomial has real coefficients(0 and 1).
 +
 +
A maximal ideal is the ideal I of a ring R where I and R are the closest that they can be. Alternatively, if M is an ideal with I as a subset of M, then M must be either I or R.
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Example: kR is a maximal ideal of R if k is prime and R is a ring of integers.
  
  

Revision as of 14:55, 3 December 2020

Hilbert’s Nullstellensatz: Proofs and Applications

Author: Ryan Walter


Table of Contents:

1. Introduction

2. Vocab

3. Theorem

     a. Weak
     b. Strong

4. Applications

5. Sources


Introduction:

Hilbert's Nullstellensatz is a relationship between algebra and geometry that was discovered by David Hilbert in 1900. Nullstellensatz is a German word that translates roughly to “Theorem of Zeros” or more precisely, “Zero Locus Theorem.” The Nullstellensatz is a foundational theorem that greatly advanced the study of algebraic geometry by proving a strong connection between geometry and a branch of algebra called commutative algebra. Both the Nullstellensatz and commutative algebra focus heavily on ‘rings,’ which will be defined in the vocabulary section.

Vocab:

A polynomial ring is defined as R[x] = R0x0 + R1x1+…+Rnxn, where R0, R1, … Rn are all coefficients in R. This polynomial ring is not a function and these x’s are not replaced by numbers; they are a symbol rather than a value. . Usually, when and R term is zero, the entire term is omitted.

Example: R(x) = 1 + 2x + 0x2 + 0x3 + 0x4 + 3x5 can be written as R(x) = 1 + 2x + 3x5


An two-sided ideal, or simply ideal, of a ring is a special type of ring where any two numbers that are part of the set R, are also part of the set I when added together (a,b ∈ I, a+b ∈ I) and when a number from ring I and a number from the ring R are multiplied together, the product are a part of ring I. (a ∈ I, r ∈ R, ar ∈ I). In this definition, R is any given ring and I is a subset of R.

The ideal can be split further into left and right ideals, where a left ideal is found when sL∈ L, and a right ideal is found when Rs ∈ R. The order of multiplication is significant because the ideals are often displayed as matrices, and the order of multiplication is significant when multiplying matrices. In order for a ideal to be two-sided, it must be both a right and left ideal. In this definition, R is a set that is right-handed, L is a set that is left-handed, and s is a subset of L and R.

For example, {0} is an ideal for every ring, and is known as the trivial ideal.

The matrix below is the left ideal for every 2x2 matrix with real numbers.

0  1
0  1

Proof: Given the matrix of the set of R, we check by verifying sL∈ L

  s       L                         sL
0  1  *  a  b  =  0a+1c  0c+1d  =  c  d
0  1     c  d     0a+1c  0c+1d     c  d

sL only has two elements, c and d, which are elements of L. Therefore, this s is a left ideal for all 2x2 matrices.


The matrix below is the right ideal of a ring for all 2x2 matrix with real numbers.

1  1
0  0

Proof: Given the matrix of the set of R, we check by verifying Lr ∈ L

  R        s                        Rs
a  b  *  1  1  =  1a+0b  1a+0b  =  a  a
c  d     0  0     1c+0d  1c+0d     c  c

Rs only has two elements, a and c, which are elements of R. Therefore, this s is a right ideal for all 2x2 matrices.

A field is algebraically closed if every polynomial ring’s coefficient f∈A has a root that is also in A. More simply, this means that there exists some x∈A where f(x) = 0. It is important to note that no finite field can be algebraically closed, because if the points are f1 , f2, .. fn, then the polynomial (x-f1)(x-f2)…(x-fn)+1 has no zeros that are a part of F.

Examples: x2+1 =0. A field comprised of only real numbers is not algebraically closed because there are no real numbers that can solve this polynomial despite the fact that the polynomial has real coefficients(0 and 1).

A maximal ideal is the ideal I of a ring R where I and R are the closest that they can be. Alternatively, if M is an ideal with I as a subset of M, then M must be either I or R.

Example: kR is a maximal ideal of R if k is prime and R is a ring of integers.



Theorem:

Applications:

Sources:

Alumni Liaison

Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010