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<center><math>\int_{0}^{1}\frac{x^2-1}{ln(x)}\ dx</math></center>
 
<center><math>\int_{0}^{1}\frac{x^2-1}{ln(x)}\ dx</math></center>
  
The graph of this function looks like this: [[Image: graphST.jpeg]]
+
The graph of this function looks like this:  
 +
<center>[[Image: graphST.jpeg]]</center>
 +
 
 +
The antiderivative of this function may turn out to be ugly as it involves solving with the exponential and logarithmic integral, but this function can be solved if we using differentiation under the integral sign. Therefore, let's define a more basic function:
 +
<center>F(b) = <math>\int_{0}^{1}\frac{x^b-1}{ln(x)}\ dx</math></center>

Revision as of 01:04, 3 December 2020

Worked Solution using Feynman's Technique

To provide a better understanding of how Feynman's technique, here is another example. Let this function:

$ \int_{0}^{1}\frac{x^2-1}{ln(x)}\ dx $

The graph of this function looks like this:

GraphST.jpeg

The antiderivative of this function may turn out to be ugly as it involves solving with the exponential and logarithmic integral, but this function can be solved if we using differentiation under the integral sign. Therefore, let's define a more basic function:

F(b) = $ \int_{0}^{1}\frac{x^b-1}{ln(x)}\ dx $

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva