(Created page with "=Applications with Physics= Feynman's integral when used in different types of integrals can simplify mathematicians' and students' lives. We can use this technique in solvin...")
 
 
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=Applications with Physics=
 
=Applications with Physics=
  
Feynman's integral when used in different types of integrals can simplify mathematicians' and students' lives. We can use this technique in solving arduous definite and improper definite integrals. To give an idea of how students can use this method to simplify their lives when dealing with such integrals, here are some examples.  
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When used in different types of integrals, Feynman's integral can simplify mathematicians' and students' lives. We can use this technique in solving arduous definite and improper definite integrals. To better apply this technique, physicists use this trick to solve problems in quantum physics. They tweak the equations or functions and introduce ideas from complex numbers to simplify their functions. To give an example of how this is done, let's have a look at the following example
  
=Definite Integral=
 
 
When given a definite integral such as,
 
When given a definite integral such as,
 
<center><math>\int_{0}^{\pi} e^{cos(x)}cos(sin(x)) dx</math></center>
 
<center><math>\int_{0}^{\pi} e^{cos(x)}cos(sin(x)) dx</math></center>

Latest revision as of 01:36, 5 December 2020

Applications with Physics

When used in different types of integrals, Feynman's integral can simplify mathematicians' and students' lives. We can use this technique in solving arduous definite and improper definite integrals. To better apply this technique, physicists use this trick to solve problems in quantum physics. They tweak the equations or functions and introduce ideas from complex numbers to simplify their functions. To give an example of how this is done, let's have a look at the following example

When given a definite integral such as,

$ \int_{0}^{\pi} e^{cos(x)}cos(sin(x)) dx $

Using what we learnt from feynman's technique, we can modify this as a function of:

$ T(b) = \int_{0}^{\pi} e^{bcos(x)}cos(bsin(x)) dx $

Back to Feynman Integrals

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