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From this we can see that the number of groups of order n depends more on the prime structure then on its size.  
 
From this we can see that the number of groups of order n depends more on the prime structure then on its size.  
  
Look at this graph to help explain this notion:  
+
Look at this table to help explain this notion:  
  
<br> [[Image:C:\Users\Mark\Documents\n-groups.jpg|frame]]<br>  
+
<br> <br>  
  
 
== Regular p-groups  ==
 
== Regular p-groups  ==

Revision as of 12:57, 30 November 2013

Mark Rosinski, markrosi@purdue.edu Joseph Lam, lam5@purdue.edu Beichen Xiao, xiaob@purdue.edu

Outline:

Origin 

-History of the Sylow Theorems/ p-groups

P-Groups -Definition

-Regular p-groups

-Relationship to Abelian Groups

-Application

-Frattini Subgroup


Sylow Theorems -Application

I plan on deleting everything above this after we have completed the paper.  I planned on just using the outline as a guide. 

I've been using these websites: 

http://math.berkeley.edu/~sikimeti/SylowNotes.pdf

http://omega.albany.edu:8008/Symbols.html (this is Tex symbols)

http://www.ams.org/journals/bull/2001-38-03/S0273-0979-01-00909-0/S0273-0979-01-00909-0.pdf

and also the pdf emailed to you

http://groupprops.subwiki.org/wiki/Regular_p-group regular p-group

http://people.maths.ox.ac.uk/craven/docs/lectures/pgroups.pdf this one is alm[[|]]ost about everything.



Email the group to see if anyone else is currently making changes before you begin making changes yourself!!!

P-groups

Definitions:

  • Let p be a prime p be an integer greater or equal to 0. A p-group is a group of order pn.
  • A subgroup of order pk for some k ≥ 1 is called a p-subgroup.
  • If |G| = pαm where p does not divide m, then a subgroup of order pα is called a Sylow p-subgroup of G.


Propositions:

If G is a p-group then G contains an element of order p.

  1. If G is a p-group then Z(G)cannot be equal to {1}
  2. Let p be a prime and let G be a group of order p2. Then G is abelian.
  3. If G is a p-group of order pa, then there exists a chain, {1} is contained in N1 contained in N2 contained in...contained in Na-1 contained in Gof normal subgroups of G, such that |Ni|=pi.


All content above and proofs of these Propositions can be found here


Further Information on p-groups:

  • Lie Algebras
    • A lie ring is a set R with two binary operations - addition and the Lie bracket - such that
      • (R,+) is an abelian group;
      • The bracket operation distributes over addition;
      • [x,x] = 0 for all x in R;
      • [[x,y],z]+[[y,z],x]+[[z,x],y]=0 for all x,y,z in R.
    • If F is a field, and R is an F-vector space with a[x,y]=[ax,y] then R is a Lie algebra.
    • To every finite p-group one can associate a Lie ring L(G), and if G/G' is abelian then L(G) is actually a lie algebra over the finite field GF(p).
      • Proposition: Let φ be an automorphism of the finite p-group G. Then φ induces an automorphism on L(G), and if φ has order prime to p, then the induced automorphism has the same order.
  • Number of Groups
    • Let g(n) denote the number of groups of order n.
      • i) g(p)=1 for p a prime.
      • ii) if p<q, then g(pq)=1 if q is not congruent to 1 mod p, and g(pq)=2 otherwise.
      • iii) g(p2)=2.
      • iv) g(p3)=5.

From this we can see that the number of groups of order n depends more on the prime structure then on its size.

Look at this table to help explain this notion:



Regular p-groups

Definitons:

  • For every $ a, b \in G $ there exists $ c \in [<a,b>,<a,b>] $ such that apbp = (a'b)pcp
  • For every $ a, b \in G $ there exist $ c_1 , c_2 , . . . , c_k \in [<a,b>,<a,b>] $ such that $ a^p b^p = (ab)^p c^p _1 c^p _2 . . . c^p _k $
  • For evert $ a, b \in G $ and every natural number n there exist Failed to parse (syntax error): c_1 , c_2 , . . . , c_k \in {,a,b>,<a,b>]
such that $ a^q b^q = (ab)^q c^q _1 c^q _2 . . . c^q _k $ where q = pn



Sylow's Theorems

Notation:

Sylp(G) = the set of Sylow p-subgroups of G

np(G)= the # of Sylow p-subgroups of G =|Sylp(G)|

Theorems:

Let G be a group of order pαm, where p is a prime, m≥1, and p does not divide m.  Then:

  1. Sylp(G) cannot be the empty set. 
  2. All Sylow p-subgroups are conjugate in G. To expand, if P1 and P2 are both Sylow p-subgroups, then there is some g in G such that P1=gP1g-1.                           In particular, np(G)=(G:NG(P)).
  3. Any p-subgroup of G is contained in a Sylow p-subgroup
  4. np(G) is congruent to 1 mod p. 

All content from this section and proofs of these Theorems can be found here




Extra Information

For students looking for extensive history on p-groups, Sylow's Theorems and finite simple groups in general you can find this information here

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