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Febuary 4th:
 
Febuary 4th:
  
question number 24.) in the homework asks how many ways are there for 10 women an dsix men to stand next to each other in a line.   
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question number 24.) in the homework asks how many ways are there for 10 women and six men to stand next to each other in a line.   
  
Answer to the question i think is because you have 16 men and women all togeather and order is not important you have 16 chocies for the first position, and then 15 chocies for the second, and so on. therefore the answer is 16! which is 16*15*14*13*12*11*10*9*8*7*6*5*4*3*2*1= 2.09^e13
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Answer to the question I think is because you have 16 men and women all togeather and order is not important you have 16 chocies for the first position, and then 15 chocies for the second, and so on. therefore the answer is 16! which is 16*15*14*13*12*11*10*9*8*7*6*5*4*3*2*1= 2.09^e13
  
 
But what if one of the stipulations was that two men stand next to each other. then what you would do is (16!/2!14!)= 120
 
But what if one of the stipulations was that two men stand next to each other. then what you would do is (16!/2!14!)= 120

Latest revision as of 04:31, 5 February 2009

January 29th:

My schedual is clear mon. wed. and fri. mornnings untill 2:30p.m., and then in the evenings after 4:30p.m. any day of the week.

My purdue email: lawrencn@purdue.edu

Febuary 4th:

question number 24.) in the homework asks how many ways are there for 10 women and six men to stand next to each other in a line.

Answer to the question I think is because you have 16 men and women all togeather and order is not important you have 16 chocies for the first position, and then 15 chocies for the second, and so on. therefore the answer is 16! which is 16*15*14*13*12*11*10*9*8*7*6*5*4*3*2*1= 2.09^e13

But what if one of the stipulations was that two men stand next to each other. then what you would do is (16!/2!14!)= 120

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Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett