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I like your examples and your consideration of all cases of input signals x(t) (including non-bounded ones).  Your definitions get the point across, though saying <math>|x(t)| < \epsilon </math> isn't technically correct, assuming you mean <math>\epsilon</math> to be a real constant.  (One should say <math>\forall t \in \mathbb{R}, |x(t)| < \epsilon </math>.)  -Brian Thomas
 
I like your examples and your consideration of all cases of input signals x(t) (including non-bounded ones).  Your definitions get the point across, though saying <math>|x(t)| < \epsilon </math> isn't technically correct, assuming you mean <math>\epsilon</math> to be a real constant.  (One should say <math>\forall t \in \mathbb{R}, |x(t)| < \epsilon </math>.)  -Brian Thomas
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Very clear answer,  I had no problem understanding the wording. As far as I know it was correct.
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-Collin Phillips

Revision as of 07:50, 18 September 2008

Your answer is pretty good. I liked how it was to-the-point yet informative. It is pretty awesome, just shy of how awesome mine is. -Virgil Hsieh

I like your examples and your consideration of all cases of input signals x(t) (including non-bounded ones). Your definitions get the point across, though saying $ |x(t)| < \epsilon $ isn't technically correct, assuming you mean $ \epsilon $ to be a real constant. (One should say $ \forall t \in \mathbb{R}, |x(t)| < \epsilon $.) -Brian Thomas

Very clear answer, I had no problem understanding the wording. As far as I know it was correct. -Collin Phillips

Alumni Liaison

Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010