(Began SHA-1 walkthrough)
m
Line 29: Line 29:
 
  = 0100100001100101011011000110110001101111<span style="color:red">1</span>
 
  = 0100100001100101011011000110110001101111<span style="color:red">1</span>
  
Since hello is less than 448 we add 0’s until the string is 448 bits long:
+
Since "Hello" is less than 448 we add 0’s until the string is 448 bits long:
  
 
  = 01001000011001010110110001101100011011111<span style="color:red">000…0</span> (len = 448 bits)
 
  = 01001000011001010110110001101100011011111<span style="color:red">000…0</span> (len = 448 bits)

Revision as of 00:21, 29 November 2022

Hey Today we are talking about code anoymization. Let's Define an equation: $ Y=x^2 $


SHA-1 Walkthrough

Step 1:

Initialize 5 Random strings

H1 = 0x67452301
H2 = 0xEFCDAB89
H3 = 0x98BADCFE
H4 = 0x10325476
H5 = 0xC3D2E1F0

Step 2:

Take the word you want to hash (in binary), and append a 1 to the end of it. Then append as many zeros as it takes to make it divisible by 512, with the length of the message in a 64 bit integer appended at the end of the string.

Example:

The word "Hello" in binary is:

                     01001000 01100101 01101100 01101100 01101111
                       (H)      (e)      (l)      (l)      (o)

Add 1 to the end:

= 01001000011001010110110001101100011011111

Since "Hello" is less than 448 we add 0’s until the string is 448 bits long:

= 01001000011001010110110001101100011011111000…0 (len = 448 bits)

Lastly take the length of the string before processing (40 bits in this case) append that as a 64 bit integer

= ...0000101000 (length of added bits = 64)

So total length is 512 in this example

010010000110010101101100011011000110111110………0101000

Step 3

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Ryne Rayburn