• A(t) = the integral of e^(-x) dx from 0 to t V(t) = the integral of Pi*[e^(-x)]^2 dx from 0 to t
    1 KB (245 words) - 18:31, 6 October 2008
  • ...with the limits of integration when you take the derivative of a definite integral?
    645 B (120 words) - 18:05, 6 October 2008
  • ...pi/2 instead of pi/4 because you have to bring out a 2 before you take the integral meaning that you have to multiply the first part of the answer from above b Now in the first integral substitute <math>v=2x</math> Therefore <math>dv=2dx</math> and when x=0, v=
    2 KB (315 words) - 14:23, 8 October 2008
  • <math>\int\frac{6*2du}{1+u^2}</math> an easily-integrated integral. :) [[User:Jhunsber|Jhunsber]]
    794 B (147 words) - 14:30, 8 October 2008
  • ...heir powers are equal), you can use this trick to drastically simplify the integral. It's a case that I don't think we covered in reading or lecture, but it d
    3 KB (584 words) - 10:12, 21 October 2008
  • ...it eventually, but the inverse sin just gets worse and worse. Actually the integral of the inverse sin is just the inverse sin minus some radical. So it just c This looks better... but then I can't figure out how to solve that integral. Anyone? I've tried using the bottom as dv and going back to the inverse si
    2 KB (289 words) - 12:27, 14 October 2008
  • ...es to <math>-\frac{3}{2}</math>, And I use partial fractions on the second integral: I solve for the first integral, leaving:
    1 KB (224 words) - 08:12, 14 October 2008
  • Again we want to estimate the error for this integral on the interval x is between 0 and 1
    3 KB (599 words) - 08:47, 13 November 2008
  • That works wonder if the first part of the integral is x to the third power, but in this case, you end up with an uneliminatabl
    858 B (146 words) - 11:37, 1 November 2008
  • ...ide of the equation the closer we get to <math>\frac{\pi}{4}</math>. This integral can therefore be called the error function.
    10 KB (1,816 words) - 15:32, 8 December 2008
  • ...te integral converge for anyone? Also, if you are having trouble with the integral, take a look at the derivatives of inverse hyperbolic functions. --[[User:
    3 KB (531 words) - 09:53, 28 October 2008
  • ...x = 7 or 8, and then decreases as x goes to infinity. In order to use the Integral test, however, doesn't the function have to be continually decreasing over I got that this one diverged by Integral Test after I ended up using the integral...Mathematica said the same. Anyone agree that it diverges? I just want t
    1 KB (190 words) - 12:16, 3 November 2008
  • ...amental theorem of calculus, because it allows one to compute the definite integral of a function by using any one of its infinitely many anti derivatives. Thi
    343 B (52 words) - 17:32, 14 September 2008
  • ''computation of the integral is the same as shown in the section above''
    650 B (86 words) - 06:49, 3 September 2008
  • Since we already know that the integral equals <math> 2\pi </math>, dividing that by <math> 4\pi </math> will yield
    897 B (142 words) - 10:00, 4 September 2008
  • The solution to this integral is 1/4.
    329 B (60 words) - 14:39, 4 September 2008
  • ...alogue linear electronics a capacitor is represented mathematically by the integral <math> y(t) = 1/C\int_{-\infty}^t x(\tau) d\tau </math> which is also a sys
    1 KB (182 words) - 19:20, 18 September 2008
  • we can determine the output using convolution integral
    1 KB (215 words) - 14:56, 26 September 2008
  • ...Fourier transform X(w) and compute its inverse Fourier transform using the integral formula. (Make it difficult).
    123 B (19 words) - 11:20, 3 October 2008
  • Specify a signal x(t) and compute its Fourier transform using the integral formula.( Make a hard one)
    913 B (139 words) - 12:24, 16 September 2013

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Questions/answers with a recent ECE grad

Ryne Rayburn