(New page: \int_{\{|f_n|>M\}}|f_n|\leq\int_{(0,1)}|f_n-f|)
 
Line 1: Line 1:
\int_{\{|f_n|>M\}}|f_n|\leq\int_{(0,1)}|f_n-f|
+
<math>\int_{\{|f_n|>M\}}|f_n|\leq\int_{(0,1)}|f_n-f|here</math>

Revision as of 09:41, 2 July 2008

$ \int_{\{|f_n|>M\}}|f_n|\leq\int_{(0,1)}|f_n-f|here $

Alumni Liaison

Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010