| Line 10: | Line 10: | ||
'''Answer:''' | '''Answer:''' | ||
| − | * P(H) | + | * P(H) <math>= \int_{0}^{1}P(H|Q=q) * fQ(q) dq</math><br> |
| − | * | + | * <math>= \int_{0}^{1}q^2*q dq</math><br> |
| − | * = 2/3 | + | * <math>= 2/3 |
Revision as of 04:43, 11 October 2008
Set-Up:
- Suppose you have a machine that produces random coins. (Thus, the probability of taking a coin from the machine, tossing it, and getting a 'heads' is a random variable.
- Suppose fQ(q)= 2q for 0<q<1
- If Q = q then P(H|Q=q) = q
- Below graph: fQ(q) vs q
- File:RVCoinMach.JPG ECE302Fall2008sanghavi
Question:
- Suppose you take a coin from the Random Coin Machine and toss is. What is the probability of flipping a heads?
Answer:
- P(H) $ = \int_{0}^{1}P(H|Q=q) * fQ(q) dq $
- $ = \int_{0}^{1}q^2*q dq $
- $ = 2/3 $
