(New page: Category:MA453Spring2009Walther So is g^k the element for the group? Just trying to see how g^k gives us the answer for any element. --~~~~)
 
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--[[User:Jrendall|Jrendall]] 14:02, 1 February 2009 (UTC)
 
--[[User:Jrendall|Jrendall]] 14:02, 1 February 2009 (UTC)
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I believe <math>\scriptstyle g</math> would be the element from the group. <math>\scriptstyle g</math> is arbitrary, so the proof holds for any such <math>\scriptstyle g</math> belonging to the group.
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:--[[User:Narupley|Nick Rupley]] 05:05, 4 February 2009 (UTC)

Revision as of 01:05, 4 February 2009


So is g^k the element for the group? Just trying to see how g^k gives us the answer for any element.

--Jrendall 14:02, 1 February 2009 (UTC)


I believe $ \scriptstyle g $ would be the element from the group. $ \scriptstyle g $ is arbitrary, so the proof holds for any such $ \scriptstyle g $ belonging to the group.

--Nick Rupley 05:05, 4 February 2009 (UTC)

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