(New page: You know how to do the autocorrelation and cross-correlation. <math> r_{xy}(n)=h(n)*r_{xx}(n)</math> <math>r_{yy}(n)=h(-n)*h(n)*r_{xx}(n)</math>) |
|||
| (5 intermediate revisions by 2 users not shown) | |||
| Line 2: | Line 2: | ||
| − | <math> r_{xy}(n)=h(n)*r_{xx}(n)</math> | + | <math> r_{xy}(n)=h(n)*r_{xx}(n)</math> - Cross Correlation |
| − | <math>r_{yy}(n)=h(-n)*h(n)*r_{xx}(n)</math> | + | <math>r_{yy}(n)=h(-n)*h(n)*r_{xx}(n)</math> - Autocorrelation |
| + | |||
| + | <math>*</math> means convolution. | ||
| + | |||
| + | |||
| + | If I am wrong, please reply ASAP.--[[User:Kim415|Kim415]] 09:59, 13 April 2009 (UTC) | ||
| + | |||
| + | |||
| + | |||
| + | I think that "Cross Correlation" is <math> r_{xy}(n)=h(-n)*r_{xx}(n)</math> | ||
| + | |||
| + | not,<math> r_{xy}(n)=h(n)*r_{xx}(n)</math>. | ||
| + | |||
| + | Because,<math> r_{xy}(n)=x(n)*y(-n)=x(n)*(x(-n)*h(-n))=r_{xx}(n)*h(-n)</math> | ||
| + | |||
| + | You can verify that in Proakis's book (page #127) | ||
| + | |||
| + | --[[User:Kim682|Kim682]] 16:24, 23 April 2009 | ||
Latest revision as of 11:25, 23 April 2009
You know how to do the autocorrelation and cross-correlation.
$ r_{xy}(n)=h(n)*r_{xx}(n) $ - Cross Correlation
$ r_{yy}(n)=h(-n)*h(n)*r_{xx}(n) $ - Autocorrelation
$ * $ means convolution.
If I am wrong, please reply ASAP.--Kim415 09:59, 13 April 2009 (UTC)
I think that "Cross Correlation" is $ r_{xy}(n)=h(-n)*r_{xx}(n) $
not,$ r_{xy}(n)=h(n)*r_{xx}(n) $.
Because,$ r_{xy}(n)=x(n)*y(-n)=x(n)*(x(-n)*h(-n))=r_{xx}(n)*h(-n) $
You can verify that in Proakis's book (page #127)
--Kim682 16:24, 23 April 2009
