(New page: a. On the problem hint, "differentiate" means to differentiate "a" and "b". After that, you can get the answer "a" and "b".--~~~~) |
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After that, you can get the answer "a" and "b".--[[User:Kim415|Kim415]] 09:55, 13 April 2009 (UTC) | After that, you can get the answer "a" and "b".--[[User:Kim415|Kim415]] 09:55, 13 April 2009 (UTC) | ||
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| + | I believe this is correct. My understand was that you differentiate in terms of a. Then, you differentiate the original equation *not the newly obtained one via the differentiation in terms of a) in terms of b. These two equations will present the classic, and easy-to-solve, case of two-equations-and-two-unknowns. From here on out, it is basic algebra. Oh, joy! I may be wrong, however, so do not take my word for it. Also, if anyone has a better idea, please, tell me. | ||
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| + | --[[User:vhsieh|vhsieh]] 11:08, 13 April 2009 (UTC) | ||
Revision as of 08:09, 13 April 2009
a. On the problem hint, "differentiate" means to differentiate "a" and "b".
After that, you can get the answer "a" and "b".--Kim415 09:55, 13 April 2009 (UTC)
I believe this is correct. My understand was that you differentiate in terms of a. Then, you differentiate the original equation *not the newly obtained one via the differentiation in terms of a) in terms of b. These two equations will present the classic, and easy-to-solve, case of two-equations-and-two-unknowns. From here on out, it is basic algebra. Oh, joy! I may be wrong, however, so do not take my word for it. Also, if anyone has a better idea, please, tell me.
--vhsieh 11:08, 13 April 2009 (UTC)
