(New page: In other words prove that: <math> {n \choose 1} + {n \choose 3} + {n \choose 5} + ... = {n \choose 0} + {n \choose 2} + {n \choose 4} + ... </math>)
 
 
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<math> {n \choose 1} +  {n \choose 3} +  {n \choose 5} + ... = {n \choose 0} +  {n \choose 2} +  {n \choose 4} + ... </math>
 
<math> {n \choose 1} +  {n \choose 3} +  {n \choose 5} + ... = {n \choose 0} +  {n \choose 2} +  {n \choose 4} + ... </math>
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In even more simple terms, this is just a rephrasing of Corollary 2 on page 365 of the book.

Latest revision as of 03:40, 18 September 2008

In other words prove that:

$ {n \choose 1} + {n \choose 3} + {n \choose 5} + ... = {n \choose 0} + {n \choose 2} + {n \choose 4} + ... $

In even more simple terms, this is just a rephrasing of Corollary 2 on page 365 of the book.

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Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva