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How many ways are there for 10 women and 6 men to stand in a line so that no two men stand next to each other?

  • Hint* Position the women and then consider possible positions for the men

Placing the women first you have 10! ways to place them. and then you have

[ ] W [ ] W [ ] W [ ] W [ ] W [ ] W [ ] W [ ] W [ ] W [ ] W [ ]

and the [ ] are possible places where you can put a man so there are 11 choose 6 ways to put the men somewhere.

$ 10!*11!/(5!) $

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