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we can express x! as a gamma function but the derivative is kind of a mess.  If you were to take the derivative of the the rest of the function you would find
+
we can express x! as a gamma function but the derivative is kind of a mess and maybe it can get canceled out by the making the derivative = 0.  If you were to take the derivative of the the rest of the function you would find
  
 
<math> {1000000}p^{999999} * -{(n-1000000)} *(1-p)^{n-1000001} </math> = 0
 
<math> {1000000}p^{999999} * -{(n-1000000)} *(1-p)^{n-1000001} </math> = 0
 +
 +
to get the ML estimate

Revision as of 19:21, 10 November 2008

So where

$ \hat n_{ML} = \text{max}_n ( \binom{n}{1000000} p^{1000000} (1-p)^{n-1000000} ) $


we can express x! as a gamma function but the derivative is kind of a mess and maybe it can get canceled out by the making the derivative = 0. If you were to take the derivative of the the rest of the function you would find

$ {1000000}p^{999999} * -{(n-1000000)} *(1-p)^{n-1000001} $ = 0

to get the ML estimate

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Ruth Enoch, PhD Mathematics