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===Answer 1=== | ===Answer 1=== | ||
| − | + | <math> | |
No, because a set must have unique elements; sin(t+pi/2) is basically cos(t). | No, because a set must have unique elements; sin(t+pi/2) is basically cos(t). | ||
The union of both sets is a set with elements from both S1 and S2. | The union of both sets is a set with elements from both S1 and S2. | ||
S1 U S2 = {sin(t),cos(t),sin(t/2),sin(t+pi/2)} | S1 U S2 = {sin(t),cos(t),sin(t/2),sin(t+pi/2)} | ||
| + | <math> | ||
===Answer 2=== | ===Answer 2=== | ||
Write it here. | Write it here. | ||
Revision as of 21:14, 9 January 2013
Practice Problemon set operations
Consider the following sets:
$ \begin{align} S_1 &= \left\{ \sin (t), \cos (t)\right\}, \\ S_2 & = \left\{ \sin (\frac{t}{2}), \sin (t+\frac{\pi}{2})\right\}. \\ \end{align} $
Write $ S_1 \cup S_2 $ explicitely. Is $ S_1 \cup S_2 $ a set?
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Answer 1
$ No, because a set must have unique elements; sin(t+pi/2) is basically cos(t). The union of both sets is a set with elements from both S1 and S2. S1 U S2 = {sin(t),cos(t),sin(t/2),sin(t+pi/2)} <math> ===Answer 2=== Write it here. ===Answer 3=== Write it here. ---- [[2013_Spring_ECE_302_Boutin|Back to ECE302 Spring 2013 Prof. Boutin]] [[ECE302|Back to ECE302]] $
