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[[Category:MA425Fall2012Bell]] | [[Category:MA425Fall2012Bell]] | ||
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| + | This isn't directly related to the practice exam, but is concerning a fact discussed in class. | ||
| + | In one of the first lessons an important fact was provided. Namely, Suppose u is continuously a differentiable function on a connected open set <math>\Omega</math> and that <math>\nabla u \equiv 0</math> Then u must be constant on <math>\omega</math>. | ||
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| + | How/Why is | ||
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| + | <math> 0 = \int\nabla u\ ds </math> | ||
Revision as of 09:32, 30 September 2012
Practice material for Exam 1 collaboration space
You can easily talk about math here, like this:
$ e^{i\theta} = \cos \theta + i \sin \theta. $
Is this the Cauchy Integral Formula?
$ f(a)=\frac{1}{2\pi i}\int_\gamma \frac{f(z)}{z-a} \ dz $
This isn't directly related to the practice exam, but is concerning a fact discussed in class.
In one of the first lessons an important fact was provided. Namely, Suppose u is continuously a differentiable function on a connected open set $ \Omega $ and that $ \nabla u \equiv 0 $ Then u must be constant on $ \omega $.
How/Why is
$ 0 = \int\nabla u\ ds $
