Revision as of 10:50, 28 October 2008 by Idryg (Talk)

Okay, so the problem is:

$ a_n = \frac{n!}{n^n} $

And, it hints to compare this with $ \frac{1}{n} $.

I don't get really how to compare these two.. I mean, I can see that the denominator of $ a_n $ will grow much faster than the numerator. I'm guessing the limit approaches 0 as n approaches infinity, but I'm not sure how to mathematically show that $ a_n < \frac{1}{n} $

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BSEE 2004, current Ph.D. student researching signal and image processing.

Landis Huffman